Solve the Nested Square Root: Finding √√12

Solve the following exercise:

12= \sqrt{\sqrt{12}}=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:06 Let's solve this problem step by step.
00:09 Remember, a regular root is a square root, or a root of order two.
00:14 If a number A is raised to power B inside a root of order C,
00:19 the result is A raised to power of B multiplied by C. Let's calculate it together.
00:25 We apply this formula to our exercise.
00:29 and calculate the multiplication.
00:32 Great job! We've found the solution.

Step-by-step written solution

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1

Understand the problem

Solve the following exercise:

12= \sqrt{\sqrt{12}}=

2

Step-by-step solution

In order to solve the following expression 12 \sqrt{\sqrt{12}} , it needs to be simplified using the properties of exponents and roots. Specifically, we apply the rule that states that the square root of a square root can be expressed as a fourth root.

Let's break down this solution step by step:

  • First, represent the inner 12 \sqrt{12} as a power: 121/2 12^{1/2} .

  • Next, take the square root of this result, which involves raising 121/2 12^{1/2} to the power of 1/2 1/2 again:
    (121/2)1/2=12(1/2)(1/2)=121/4\left(12^{1/2}\right)^{1/2} = 12^{(1/2) \cdot (1/2)} = 12^{1/4}.

  • According to the rules of exponents, raising an exponent to another power results in multiplying the exponents.

  • This gives us 121/4 12^{1/4} , which we can write as the fourth root of 12: 124 \sqrt[4]{12} .

In conclusion the simplification of 12 \sqrt{\sqrt{12}} is 124 \sqrt[4]{12} .

3

Final Answer

124 \sqrt[4]{12}

Practice Quiz

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Solve the following exercise:

\( \sqrt[5]{\sqrt[3]{5}}= \)

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