Solve the Nested Radical: Simplifying the Sixth Root of Square Root of 2

Solve the following exercise:

26= \sqrt[6]{\sqrt{2}}=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:06 Let's start by solving this math problem.
00:09 A regular root is the same as a square root.
00:16 Imagine a number, A, under a root of order B, inside another root of order C.
00:22 The result is A raised to the power of B divided by C.
00:28 Let's use this formula to solve our problem.
00:32 Now, calculate the order of multiplication.
00:35 And that's how we find the solution!

Step-by-step written solution

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1

Understand the problem

Solve the following exercise:

26= \sqrt[6]{\sqrt{2}}=

2

Step-by-step solution

In order to solve this problem, we must simplify the following expression 26 \sqrt[6]{\sqrt{2}} using the rule for roots of roots. This rule states that a root of a root can be written as a single root by multiplying the indices of the radicals.

  • Step 1: Identify the given expression 26 \sqrt[6]{\sqrt{2}} .

  • Step 2: Recognize that the inner root, 2\sqrt{2}, can be expressed as 22\sqrt[2]{2}.

  • Step 3: Visualize 26 \sqrt[6]{\sqrt{2}} as 226 \sqrt[6]{\sqrt[2]{2}} .

  • Step 4: Apply the rule amn=an×m\sqrt[n]{\sqrt[m]{a}} = \sqrt[n \times m]{a}.

  • Step 5: Multiply the indices: 6×2=126 \times 2 = 12.

  • Step 6: Replace the compound root with the single root: 212\sqrt[12]{2}.

Thus, the expression 26 \sqrt[6]{\sqrt{2}} simplifies to 212 \sqrt[12]{2} .

Therefore, the solution to the problem is 212 \sqrt[12]{2} .

3

Final Answer

212 \sqrt[12]{2}

Practice Quiz

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Solve the following exercise:

\( \sqrt[5]{\sqrt[3]{5}}= \)

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