Solve the following equation:
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Solve the following equation:
The following is a quadratic equation:
This is due to the fact that there is a quadratic term (meaning raised to the second power),
The first step in solving a quadratic equation is always arranging it in a form where all terms on one side are ordered from highest to lowest power (in descending order from left to right) and 0 on the other side,
Then we can choose whether to solve it using the quadratic formula or by factoring/completing the square.
The equation in the problem is already arranged, so let's proceed to solve it using the quadratic formula,
Remember:
The rule states that the roots of an equation in the form:
are:
(meaning its solutions, the two possible values of the unknown for which we get a true statement when substituted in the equation)
This formula is called: "The Quadratic Formula"
Let's return to the problem:
and solve it:
First, let's identify the coefficients of the terms:
where we noted that the coefficient includes the minus sign, and this is because in the general form of the equation we mentioned earlier:
the coefficients are defined such that they have a plus sign in front of them, and therefore the minus sign must be included in the coefficient value.
Let's continue and obtain the equation's solutions (roots) by substituting the coefficients we noted earlier in the quadratic formula:
Let's continue and calculate the expression under the root and simplify the expression:
The expression under the root is negative, and since we cannot extract a real root from a negative number, this equation has no real solutions,
Meaning - there is no real value of that when substituted in the equation will give a true statement.
Therefore, the correct answer is answer D.
No solution
a = Coefficient of x²
b = Coefficient of x
c = Coefficient of the independent number
what is the value of \( a \) in the equation
\( y=3x-10+5x^2 \)
It means there's no real number you can substitute for x that makes the equation true. The graph of this parabola never touches the x-axis, so there are no x-intercepts.
Always calculate b²-4ac before using the quadratic formula! If it's negative, you can immediately say 'no real solutions' without doing more work.
Double-check your coefficients: a=2, b=-3, c=5. Then recalculate: . The negative result is correct!
Yes, but they're complex numbers involving i (the imaginary unit). In most algebra courses, we only consider real number solutions.
Look at the graph! If the parabola opens upward (a > 0) and has a positive y-intercept (c > 0), it might not cross the x-axis. Use the discriminant to be sure.
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