Solve the Quadratic Equation: 2x²-3x+5=0 Step-by-Step

Quadratic Equations with Complex Discriminants

Solve the following equation:

2x23x+5=0 2x^2-3x+5=0

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:06 Let's find the value of X.
00:10 First, identify the coefficients in the equation.
00:21 Now, we'll use the quadratic formula. Are you ready?
00:45 Substitute the values from the problem into the formula, and solve step-by-step.
01:12 Calculate the square of each value and their products carefully.
01:26 Remember, a root cannot be a negative number.
01:38 So, there is no solution to this question. Great effort!

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the following equation:

2x23x+5=0 2x^2-3x+5=0

2

Step-by-step solution

The following is a quadratic equation:

2x23x+5=0 2x^2-3x+5=0

This is due to the fact that there is a quadratic term (meaning raised to the second power),

The first step in solving a quadratic equation is always arranging it in a form where all terms on one side are ordered from highest to lowest power (in descending order from left to right) and 0 on the other side,

Then we can choose whether to solve it using the quadratic formula or by factoring/completing the square.

The equation in the problem is already arranged, so let's proceed to solve it using the quadratic formula,

Remember:

The rule states that the roots of an equation in the form:

ax2+bx+c=0 ax^2+bx+c=0

are:

x1,2=b±b24ac2a x_{1,2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

(meaning its solutions, the two possible values of the unknown for which we get a true statement when substituted in the equation)

This formula is called: "The Quadratic Formula"

Let's return to the problem:

2x23x+5=0 2x^2-3x+5=0 and solve it:

First, let's identify the coefficients of the terms:

{a=2b=3c=5 \begin{cases}a=2 \\ b=-3 \\ c=5\end{cases}

where we noted that the coefficient includes the minus sign, and this is because in the general form of the equation we mentioned earlier:

ax2+bx+c=0 ax^2+bx+c=0

the coefficients are defined such that they have a plus sign in front of them, and therefore the minus sign must be included in the coefficient value.

Let's continue and obtain the equation's solutions (roots) by substituting the coefficients we noted earlier in the quadratic formula:

x1,2=b±b24ac2a=(3)±(3)242522 x_{1,2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{-(-3)\pm\sqrt{(-3)^2-4\cdot2\cdot5}}{2\cdot2}

Let's continue and calculate the expression under the root and simplify the expression:

x1,2=3±312 x_{1,2}=\frac{3\pm\sqrt{-31}}{2}\frac{}{}

The expression under the root is negative, and since we cannot extract a real root from a negative number, this equation has no real solutions,

Meaning - there is no real value of x x that when substituted in the equation will give a true statement.

Therefore, the correct answer is answer D.

3

Final Answer

No solution

Key Points to Remember

Essential concepts to master this topic
  • Discriminant Rule: When b²-4ac < 0, equation has no real solutions
  • Technique: Calculate (-3)²-4(2)(5) = 9-40 = -31 (negative)
  • Check: Negative discriminant means √-31 is impossible in real numbers ✓

Common Mistakes

Avoid these frequent errors
  • Attempting to solve when discriminant is negative
    Don't continue with the quadratic formula when b²-4ac < 0 = invalid square root! Negative discriminants mean no real solutions exist. Always check the discriminant first and recognize when no real solutions are possible.

Practice Quiz

Test your knowledge with interactive questions

a = Coefficient of x²

b = Coefficient of x

c = Coefficient of the independent number


what is the value of \( a \) in the equation

\( y=3x-10+5x^2 \)

FAQ

Everything you need to know about this question

What does 'no real solution' actually mean?

+

It means there's no real number you can substitute for x that makes the equation true. The graph of this parabola never touches the x-axis, so there are no x-intercepts.

How do I know when to check the discriminant first?

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Always calculate b²-4ac before using the quadratic formula! If it's negative, you can immediately say 'no real solutions' without doing more work.

What if I made an error and the discriminant should be positive?

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Double-check your coefficients: a=2, b=-3, c=5. Then recalculate: (3)24(2)(5)=940=31 (-3)^2 - 4(2)(5) = 9 - 40 = -31 . The negative result is correct!

Are there any solutions at all to this equation?

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Yes, but they're complex numbers involving i (the imaginary unit). In most algebra courses, we only consider real number solutions.

How can I tell if a quadratic has no real solutions without solving?

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Look at the graph! If the parabola opens upward (a > 0) and has a positive y-intercept (c > 0), it might not cross the x-axis. Use the discriminant to be sure.

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