Solve the following equation:
4x2+x−141=0
To solve this quadratic equation, we'll follow these steps:
- Step 1: Eliminate fractions and rearrange the equation.
- Step 2: Use the Quadratic Formula to find the solutions.
- Step 3: Simplify the solutions for x.
Now, let's work through each step:
Step 1: The given equation is 4x2+x−141=0.
First, multiply every term by 4 to eliminate the fraction:
x2+4x−5=0
Step 2: The equation is now in the standard form ax2+bx+c=0 with a=1, b=4, and c=−5.
Step 3: Apply the Quadratic Formula:
x=2a−b±b2−4ac
Substitute the values of a, b, and c:
x=2×1−4±42−4×1×(−5)
x=2−4±16+20
x=2−4±36
Simplify the square root and solve for x:
x=2−4±6
Calculating the two possible solutions:
x1=2−4+6=22=1
x2=2−4−6=2−10=−5
Therefore, the solutions to the quadratic equation are x1=1 and x2=−5.
The correct choice corresponds to the answer: x1=1,x2=−5.
x1=1,x2=−5