Solve the Quadratic Equation: X²+4X+4=0 Step-by-Step

Question

Solve for X:

X2+4X+4=0 X^2+4X+4=0

Video Solution

Solution Steps

00:00 Find X
00:03 Note the coefficients, each number is as if multiplied by 1
00:10 Use the roots formula
00:19 Substitute appropriate values according to the given data and solve for X
00:25 Calculate the products and the square
00:35 And this is the solution to the question

Step-by-Step Solution

To solve the quadratic equation X2+4X+4=0 X^2 + 4X + 4 = 0 , we can attempt to factor it as a perfect square trinomial.

  • Step 1: Recognize that the equation is a perfect square trinomial because it can be written as (X+2)2 (X + 2)^2 . The relationship is (X+2)(X+2)=X2+4X+4 (X + 2)(X + 2) = X^2 + 4X + 4 .
  • Step 2: Set the factored equation equal to zero: (X+2)2=0 (X + 2)^2 = 0 .
  • Step 3: Solve for X X by setting X+2=0 X + 2 = 0 .
  • Step 4: Solving X+2=0 X + 2 = 0 gives X=2 X = -2 .

Therefore, the solution to the equation is X=2 X = -2 .

Thus, the correct answer choice is x=2 x = -2 , corresponding to choice 1.

Answer

x=2 x=-2