Solve the Quadratic Equation x² + 3x + 2 = 0 by Factoring

x2+3x+2=0 x^2+3x+2=0

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find X
00:03 Let's look at the coefficients (each number is actually multiplied by 1)
00:10 Let's use the roots formula to find the possible solutions
00:17 Let's substitute appropriate values and solve to find the solutions
00:28 Let's calculate the square and products
00:33 The square root of 1 equals 1
00:36 These are the 2 options (addition and subtraction)
00:42 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

x2+3x+2=0 x^2+3x+2=0

2

Step-by-step solution

To solve the quadratic equation x2+3x+2=0 x^2 + 3x + 2 = 0 , we proceed as follows:

First, we identify that the equation is in standard form, where:

  • a=1 a = 1
  • b=3 b = 3
  • c=2 c = 2

Next, we attempt to factor the quadratic equation. We look for two numbers that multiply to ac=1×2=2 ac = 1 \times 2 = 2 and add up to b=3 b = 3 . The numbers 2 2 and 1 1 satisfy these conditions because 2×1=2 2 \times 1 = 2 and 2+1=3 2 + 1 = 3 .

Thus, we can factor the equation as:

x2+3x+2=(x+2)(x+1)=0 x^2 + 3x + 2 = (x + 2)(x + 1) = 0

Now, we solve for x x by setting each factor equal to zero:

  • x+2=0x=2 x + 2 = 0 \rightarrow x = -2
  • x+1=0x=1 x + 1 = 0 \rightarrow x = -1

Therefore, the solutions to the quadratic equation are x1=2 x_1 = -2 and x2=1 x_2 = -1 .

Since the problem is multiple-choice and we need to confirm the correct answer, we compare these solutions with the given choices. The correct choice is:

: x1=2,x2=1 x_1=-2, x_2=-1

Thus, the correct answer to the problem is:

\x1=2,x2=1 x_1 = -2, x_2 = -1

3

Final Answer

x1=2,x2=1 x_1=-2,x_2=-1

Practice Quiz

Test your knowledge with interactive questions

a = Coefficient of x²

b = Coefficient of x

c = Coefficient of the independent number


what is the value of \( a \) in the equation

\( y=3x-10+5x^2 \)

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