Solve the Quadratic Equation: Find X in (3x+1)² + 8 = 12

Quadratic Equations with Perfect Square Forms

Find X

(3x+1)2+8=12 (3x+1)^2+8=12

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find X
00:03 Open brackets properly according to quadratic formula
00:13 Calculate squares and multiplications
00:24 Arrange the equation so the right side equals 0
00:31 Reduce as much as possible
00:37 Examine the coefficients
00:41 Use the root formula to find possible solutions
00:50 Substitute appropriate values and solve for solutions
01:07 Calculate the square and multiplications
01:18 Calculate square root of 16
01:23 These are the 2 options (positive and negative)
01:33 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Find X

(3x+1)2+8=12 (3x+1)^2+8=12

2

Step-by-step solution

To solve the equation (3x+1)2+8=12(3x + 1)^2 + 8 = 12, we start by isolating the squared expression:

  • First, subtract 8 from both sides to simplify: (3x+1)2=128(3x + 1)^2 = 12 - 8.
  • This gives (3x+1)2=4(3x + 1)^2 = 4.

Next, we take the square root of both sides to remove the square:

  • 3x+1=±23x + 1 = \pm 2, recognizing the positive and negative roots of 4.

We now solve for xx in each case:

  • Case 1: 3x+1=23x + 1 = 2
    Subtract 1 from both sides: 3x=13x = 1
    Divide by 3: x=13x = \frac{1}{3}.
  • Case 2: 3x+1=23x + 1 = -2
    Subtract 1 from both sides: 3x=33x = -3
    Divide by 3: x=1x = -1.

Therefore, the solutions to the original equation are x1=13x_1 = \frac{1}{3} and x2=1x_2 = -1.

3

Final Answer

x1=13,x2=1 x_1=\frac{1}{3},x_2=-1

Key Points to Remember

Essential concepts to master this topic
  • Isolation: Move constant terms to isolate the squared expression first
  • Square Root: Take ±√ of both sides: 4=±2 \sqrt{4} = ±2
  • Verification: Check both solutions in original equation: (3(13)+1)2+8=12 (3(\frac{1}{3})+1)^2 + 8 = 12

Common Mistakes

Avoid these frequent errors
  • Forgetting the ± when taking square roots
    Don't write 3x+1=2 3x + 1 = 2 only = missing one solution! Every positive number has both positive and negative square roots. Always write 3x+1=±2 3x + 1 = ±2 to find both solutions.

Practice Quiz

Test your knowledge with interactive questions

a = Coefficient of x²

b = Coefficient of x

c = Coefficient of the independent number


what is the value of \( a \) in the equation

\( y=3x-10+5x^2 \)

FAQ

Everything you need to know about this question

Why do I get two answers for x?

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Quadratic equations naturally have two solutions because when you square a number, both positive and negative values give the same result. For example, 22=4 2^2 = 4 and (2)2=4 (-2)^2 = 4 .

What does the ± symbol mean exactly?

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The ± symbol means "plus or minus" - it's a shorthand for writing two separate equations. 3x+1=±2 3x + 1 = ±2 means solve both 3x+1=2 3x + 1 = 2 AND 3x+1=2 3x + 1 = -2 .

Do I always isolate the squared term first?

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Yes! Always move constants to one side before taking square roots. This makes the equation much simpler: (3x+1)2=4 (3x+1)^2 = 4 is easier to solve than (3x+1)2+8=12 (3x+1)^2 + 8 = 12 .

How do I check if both answers are correct?

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Substitute each solution back into the original equation. Both x=13 x = \frac{1}{3} and x=1 x = -1 should make the left side equal 12.

What if the number under the square root is negative?

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If you get something like (3x+1)2=4 (3x+1)^2 = -4 , there's no real solution because you can't take the square root of a negative number in real numbers.

Can I expand the squared term instead?

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You could expand (3x+1)2 (3x+1)^2 to 9x2+6x+1 9x^2 + 6x + 1 , but taking the square root directly is much faster and easier!

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