Solve the Square Root Expression: Simplifying √(2/4)

Square Root Operations with Fractional Radicands

Solve the following exercise:

24= \sqrt{\frac{2}{4}}=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:05 Let's solve this problem together.
00:09 The square root of a fraction, A over B,
00:13 is equal to the square root of A over the square root of B.
00:17 Now, let's apply this formula to our exercise.
00:25 First, let's break down four into two times two.
00:31 The square root of a product, A times B, equals the product of their individual roots.
00:37 Let's use this formula in our problem.
00:42 Simplify wherever you can.
00:45 And there you have it, that's the solution!

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the following exercise:

24= \sqrt{\frac{2}{4}}=

2

Step-by-step solution

Simplify the following expression:

Begin by reducing the fraction under the square root:

24=12= \sqrt{\frac{2}{4}}= \\ \sqrt{\frac{1}{2}}=

Apply two exponent laws:

A. Definition of root as a power:

an=a1n \sqrt[n]{a}=a^{\frac{1}{n}}

B. The power law for powers applied to terms in parentheses:

(ab)n=anbn \big(\frac{a}{b}\big)^n=\frac{a^n}{b^n}

Let's return to the expression that we obtained. Apply the law mentioned in A and convert the square root to a power:

12=(12)12= \sqrt{\frac{1}{2}}=\\ \big(\frac{1}{2}\big)^{\frac{1}{2}}=

Next use the power law mentioned in B, apply the power separately to the numerator and denominator.

In the next step remember that raising the number 1 to any power will always result in 1.

In the fraction's denominator we'll return to the root notation, again, using the power law mentioned in A (in the opposite direction):

(12)12=112212=12 \big(\frac{1}{2}\big)^{\frac{1}{2}}= \\ \frac{1^{\frac{1}{2}}}{2^{\frac{1}{2}}}=\\ \boxed{\frac{1}{\sqrt{2}}}\\ Let's summarize the simplification of the given expression:

24=12=112212=12 \sqrt{\frac{2}{4}}= \\ \sqrt{\frac{1}{2}}= \\ \frac{1^{\frac{1}{2}}}{2^{\frac{1}{2}}}=\\ \boxed{\frac{1}{\sqrt{2}}}\\ Therefore, the correct answer is answer D.

3

Final Answer

12 \frac{1}{\sqrt{2}}

Key Points to Remember

Essential concepts to master this topic
  • Simplification: Reduce fractions inside radicals before applying square root
  • Technique: Apply ab=ab \sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}} to separate numerator and denominator
  • Check: Verify (12)2=12 \left(\frac{1}{\sqrt{2}}\right)^2 = \frac{1}{2} matches original expression ✓

Common Mistakes

Avoid these frequent errors
  • Converting square root to decimal approximation
    Don't calculate √2 ≈ 1.414 and write 1/1.414 = 0.707! This loses exactness and doesn't match any answer choice. Always keep radicals in exact form like 12 \frac{1}{\sqrt{2}} unless specifically asked to approximate.

Practice Quiz

Test your knowledge with interactive questions

Solve the following exercise:

\( \sqrt{\frac{2}{4}}= \)

FAQ

Everything you need to know about this question

Why can't I just calculate √(2/4) = √0.5 ≈ 0.707?

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While this gives the correct numerical value, math problems usually want exact answers in radical form. The exact answer 12 \frac{1}{\sqrt{2}} is more precise than decimal approximations.

Is there a difference between √(1/2) and 1/√2?

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No! These are exactly the same value. The property ab=ab \sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}} shows they're equivalent expressions for the same number.

Should I rationalize the denominator to get √2/2?

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Both 12 \frac{1}{\sqrt{2}} and 22 \frac{\sqrt{2}}{2} are correct! However, since the answer choices show 12 \frac{1}{\sqrt{2}} , that's the expected form for this problem.

Why do I reduce 2/4 to 1/2 first?

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Simplifying fractions before applying operations makes calculations easier! 24 \sqrt{\frac{2}{4}} becomes the simpler 12 \sqrt{\frac{1}{2}} , reducing potential errors.

Can I check my answer by squaring it?

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Absolutely! Since (12)2=12(2)2=12 \left(\frac{1}{\sqrt{2}}\right)^2 = \frac{1^2}{(\sqrt{2})^2} = \frac{1}{2} , and this matches our original expression under the radical, we know our answer is correct.

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