Solve the Square Root Multiplication: √25 × √4

Square Root Multiplication with Perfect Squares

Solve the following exercise:

254= \sqrt{25}\cdot\sqrt{4}=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:08 Let's solve this problem together!
00:11 The square root of a number, let's call it A, multiplied by the square root of another number, let's say B,
00:19 is the same as the square root of their product, A times B.
00:24 Now, apply this formula to our exercise and find the product.
00:29 Calculate the square root of one hundred.
00:32 Great! That's how you solve this problem.

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the following exercise:

254= \sqrt{25}\cdot\sqrt{4}=

2

Step-by-step solution

We can simplify the expression directly without using the laws of exponents, since the expression has known square roots, so let's simplify the expression and then perform the multiplication:

254=52=10 \sqrt{25}\cdot\sqrt{4}=\\ 5\cdot2=\\ \boxed{10}

Therefore, the correct answer is answer C.

3

Final Answer

10 10

Key Points to Remember

Essential concepts to master this topic
  • Rule: Simplify each square root first before multiplying the results
  • Technique: 25=5 \sqrt{25} = 5 and 4=2 \sqrt{4} = 2 , then multiply: 5 × 2 = 10
  • Check: Verify that 5×2=10 5 \times 2 = 10 matches your final answer ✓

Common Mistakes

Avoid these frequent errors
  • Using the property √a × √b = √(a×b) when direct simplification is easier
    Don't calculate √25 × √4 = √(25×4) = √100 = 10 when you can directly simplify! This extra step wastes time and creates opportunities for errors. Always simplify perfect square roots first: √25 = 5, √4 = 2, then multiply 5 × 2 = 10.

Practice Quiz

Test your knowledge with interactive questions

Solve the following exercise:

\( \sqrt{\frac{2}{4}}= \)

FAQ

Everything you need to know about this question

Should I use the multiplication property of square roots here?

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While a×b=a×b \sqrt{a} \times \sqrt{b} = \sqrt{a \times b} is correct, it's faster to simplify first when dealing with perfect squares like 25 and 4. Direct simplification saves steps!

How do I know if a number is a perfect square?

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A perfect square has a whole number square root. Common ones to memorize: 1=1 \sqrt{1} = 1 , 4=2 \sqrt{4} = 2 , 9=3 \sqrt{9} = 3 , 16=4 \sqrt{16} = 4 , 25=5 \sqrt{25} = 5 , etc.

What if I can't remember the square roots?

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Think about which number times itself gives your radicand. For 25 \sqrt{25} , ask: what number × itself = 25? The answer is 5, because 5 × 5 = 25.

Can I multiply the numbers under the square root signs first?

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Yes, but it's longer! You'd get 25×4=100=10 \sqrt{25 \times 4} = \sqrt{100} = 10 . Both methods work, but simplifying perfect squares first is usually quicker.

What if one of the square roots wasn't a perfect square?

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Then you'd need to use the multiplication property: a×b=a×b \sqrt{a} \times \sqrt{b} = \sqrt{a \times b} . But when both are perfect squares, direct simplification is the way to go!

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