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To solve this problem, we'll follow these steps:
Let's break this down:
Step-by-step Solution:
1. Subtract the rightmost digit:
- Subtract 6 from 5. Since 5 is less than 6, we need to borrow from the next digits.
2. Borrowing:
- The immediate next digit is '0', so we continue borrowing to the left. We borrow 1 from the third zero (turning it into a 9), which makes the second zero a 9 and the third zero a 9, and we subtract the borrowed 1 from the 7, turning it into 6.
3. Complete the subtraction:
- For the units column (now 15 and 6), subtract to get: .
- For the tens column (now 9 and 2), subtract to get: .
- For the hundreds column (now 9 and 1), subtract to get: .
- For the thousands column (6 and 4), subtract to get: .
- For the ten-thousands column (no borrowing needed, 6 and 2), subtract to get: .
The final result after all column-based subtractions, including borrowing corrections, is: .
Therefore, the solution to the problem is .
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\( \begin{aligned} &15 \\ -& \\ &~~4 \\ &\underline{\phantom{776}} & \\ \end{aligned} \)
When borrowing from zero, you need to keep going left until you find a non-zero digit! Each zero becomes 9, and the non-zero digit decreases by 1.
Borrowing works because 10 ones = 1 ten! When you borrow 1 from the tens place, you're actually borrowing 10 ones, so 5 becomes 15.
Add your answer to the number you subtracted (subtrahend). If you get the original number (minuend), your answer is right!
Start over! Borrowing mistakes spread through the whole problem. It's faster to restart than to find and fix each error.
Yes! Always start from the ones place (rightmost column) and work left. This ensures borrowing works correctly through all place values.
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