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To solve this problem, we will perform subtraction using the vertical method:
The subtraction becomes , which is impossible as we cannot subtract a larger number from a smaller number without regrouping.
The subtraction in the ones column now reads 16 - 8 = 8.
The subtraction is complete: .
Therefore, the solution to the problem is .
568
\( \begin{aligned} &15 \\ -& \\ &~~4 \\ &\underline{\phantom{776}} & \\ \end{aligned} \)
You cannot subtract a larger number from a smaller number without regrouping! When you see 6 - 8, you need to borrow from the tens place first.
Look at each column from right to left. If the top digit is smaller than the bottom digit, you need to regroup by borrowing from the next column to the left.
When you borrow 1 ten, it becomes 10 ones. So the tens digit decreases by 1, and the ones digit increases by 10. In this problem: 7 tens became 6 tens, and 6 ones became 16 ones.
Yes! You can also count up from 8 to 576. Start at 8, then count: 8 + 2 = 10, then 10 + 566 = 576. This confirms the difference is 568.
If the tens place has 0, you need to keep borrowing from the hundreds place first! Change the hundreds digit, make the tens place 10, then borrow from there.
Place value alignment is crucial! The ones digits must line up in the ones column, tens in tens column, etc. This ensures you're subtracting the right values.
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