Subtract 54,636 from 80,004: Vertical Format Solution

Video Solution

Solution Steps

00:00 Solve

00:03 Each time we subtract 2 digits, and then we place

00:06 4 is less than 6

00:09 We want to borrow from the larger digits

00:12 Both tens and hundreds equal 0 so we'll borrow from the thousands

00:15 What will change the ten thousands from 8 to 7

00:20 And now we'll have 10 instead of 0, in thousands!

00:23 And we'll borrow from thousands to hundreds

00:26 We'll continue with the same method until we reach the ones

00:42 We'll borrow from tens to ones, and we'll have 14 instead of 4 in ones!

00:51 Subtract ones from ones, and place in ones

00:56 Subtract tens from tens, and place in tens

00:59 Subtract hundreds from hundreds, and place in hundreds

01:06 Subtract thousands from thousands, and place in thousands

01:11 Subtract ten thousands from ten thousands, and place

01:15 And that's the solution to the problem

Step-by-Step Solution

To solve this subtraction problem, we will perform vertical subtraction, paying close attention to borrowing across zeros:

Step-by-step solution:

Write the numbers such that they align vertically, with the larger number on top and the smaller number directly below each corresponding digit:

$\begin{aligned} &80004 \\ -&54636 \\ &\overline{\phantom{77600}} & \\ \end{aligned}$

Start subtracting from the rightmost digit:
1. Units place: $4 - 6$ . Since 4 is less than 6, borrow 1 from the tens place (next digit).
2. Tens place: Now, treat it as $10 - 3$ , but since you borrowed 1 for the units place, it becomes $9 - 3 = 6$ .
3. Hundreds place: Borrow from the thousands place since you need a digit to make $0 - 6$ . It becomes $10 - 6 = 4$ .
4. Thousands place: Now subtract from what remains after borrowing from it, $9 - 4$ , which equals 5.
5. Ten-thousands place: Since you borrowed to the right, $7 - 5 = 2$ in this position.
The subtraction yields the result as follows:

$\begin{aligned} &9560 14 \\ -&\phantom{0}54636 \\ &\phantom{0}\underline{25368} & \\ \end{aligned}$

Therefore, the solution to the subtraction problem is $\mathbf{25368}$ .