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To solve this system using the elimination method, we'll follow these steps:
The second equation is . Multiply it by 4:
The first equation is .
Adding the scaled second equation gives:
Solving gives:
Divide both sides by :
Use :
Subtract 14 from both sides:
Multiply by :
Thus, the solution to the system is and .
Therefore, the solution to the problem is .
\( \begin{cases} x+y=8 \\ x-y=6 \end{cases} \)
We want to eliminate one variable by making coefficients opposites. Since the first equation has and the second has , multiplying by 4 gives us , which cancels perfectly!
Write each step carefully! When you have , they cancel to give 0. For , you're adding two negatives to get .
Yes! But elimination is often cleaner for this system because the coefficients work out nicely. With substitution, you'd need to solve first, then substitute.
Substitute and into both original equations:
Nothing wrong with that! The solution point is in the third quadrant of the coordinate plane. Many systems have solutions with negative coordinates.
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