Solve the following equations for x and y using the substitution method:
{42x−3y+5x−y=3082y+x−43y−x=12
To solve this system, we'll first simplify and manipulate the equations to perform substitution. Let's begin:
The first equation is 42x−3y+5x−y=30.
To eliminate the fractions, multiply through by 20 (the least common multiple of 4 and 5):
20(42x−3y)+20(5x−y)=20×30
Simplifying each term gives:
5(2x−3y)+4(x−y)=600
Expanding the terms:
10x−15y+4x−4y=600
Combine like terms:
14x−19y=600 [Equation (1)]
Next, let's work on the second equation: 82y+x−43y−x=12.
Multiply through by 8 to clear the denominators:
8(82y+x)−8(43y−x)=8×12
Simplifying each term gives:
2y+x−2(3y−x)=96
Expanding the terms:
2y+x−6y+2x=96
Combine like terms for a simplified second equation:
3x−4y=96 [Equation (2)]
Now let's use substitution:
From Equation (2), solve for x:
3x=4y+96
x=34y+96
Substitute this expression for x in Equation (1):
14(34y+96)−19y=600
Multiply through by 3 to clear the fraction:
14(4y+96)−57y=1800
56y+1344−57y=1800
Combine like terms:
−y+1344=1800
Solve for y:
−y=1800−1344=456
y=−456
Substitute y=−456 back into the expression for x:
x=34(−456)+96
x=3−1824+96
x=3−1728
x=−576
Thus, the solution for the system is:
x=−576,y=−456
After verifying against the provided answer choices, the solution is consistent with choice 4.
Therefore, the solution to the problem is x=−576,y=−456.
x=−576,y=−456