Solve x²-(x+4)²=40: Perfect Square Binomial Challenge

Question

x2(x+4)2=40 x^2-(x+4)^2=40

Video Solution

Solution Steps

00:00 Find X
00:03 We'll use shortened multiplication formulas to open the brackets
00:29 Solve the multiplication and square
00:37 Negative times positive is always negative
00:55 Simplify what we can
01:00 Isolate X
01:22 And this is the solution to the question

Step-by-Step Solution

To solve the equation x2(x+4)2=40 x^2 - (x+4)^2 = 40 , follow these steps:

  • Step 1: Expand the square (x+4)2 (x+4)^2 .
  • Step 2: Substitute the expansion into the original equation.
  • Step 3: Simplify the resulting expression.
  • Step 4: Solve the simplified equation for x x .

Let's work through each step:

Step 1: Expand (x+4)2 (x+4)^2 :
(x+4)2=x2+8x+16(x+4)^2 = x^2 + 8x + 16

Step 2: Substitute this into the original equation:
x2(x2+8x+16)=40 x^2 - (x^2 + 8x + 16) = 40

Step 3: Simplify the equation:
x2x28x16=40 x^2 - x^2 - 8x - 16 = 40

Upon simplification, the equation becomes:
8x16=40 -8x - 16 = 40

Step 4: Solve for x x :
Add 16 to both sides:
8x=56 -8x = 56

Divide by 8-8:
x=568=7 x = -\frac{56}{8} = -7

Therefore, the solution to the problem is x=7 x = -7 .

Answer

x=7 x=-7