Solve (8+3x)² = (5x+3)² - (4x)²: Perfect Square Equation

Perfect Squares with Difference of Squares

(8+3x)2=(5x+3)2(4x)2 (8+3x)^2=(5x+3)^2-(4x)^2

x=? x=\text{?}

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find X
00:06 Use the shortened multiplication formulas to open the brackets
00:18 When 8 is A
00:21 And 3X is B
00:25 Substitute according to the formula and solve
00:39 Solve the squares and multiplications
01:09 Use the shortened multiplication formulas to open the brackets
01:30 Solve the squares and multiplications
01:58 Collect terms
02:05 Reduce what's possible
02:17 Isolate X
02:51 And this is the solution to the problem

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

(8+3x)2=(5x+3)2(4x)2 (8+3x)^2=(5x+3)^2-(4x)^2

x=? x=\text{?}

2

Step-by-step solution

To solve the equation (8+3x)2=(5x+3)2(4x)2 (8 + 3x)^2 = (5x + 3)^2 - (4x)^2 , we'll follow these steps:

  • Step 1: Simplify each side of the equation using known algebraic identities.
  • Step 2: Solve for x x after simplifying the equation.

Step 1: Let's expand each side of the equation.

The left side is (8+3x)2=82+283x+(3x)2=64+48x+9x2 (8 + 3x)^2 = 8^2 + 2 \cdot 8 \cdot 3x + (3x)^2 = 64 + 48x + 9x^2 .

For the right side, we use the difference of squares identity:

(5x+3)2(4x)2=((5x+3)(4x))((5x+3)+(4x)) (5x + 3)^2 - (4x)^2 = \left((5x + 3) - (4x)\right)\left((5x + 3) + (4x)\right)

Simplifying each:

(5x+3)(4x)=x+3 (5x + 3) - (4x) = x + 3

(5x+3)+(4x)=9x+3 (5x + 3) + (4x) = 9x + 3

So, the right side becomes (x+3)(9x+3)=x(9x+3)+3(9x+3)=9x2+3x+27x+9=9x2+30x+9 (x + 3)(9x + 3) = x(9x + 3) + 3(9x + 3) = 9x^2 + 3x + 27x + 9 = 9x^2 + 30x + 9 .

Now equate the simplified expressions from both sides:

64+48x+9x2=9x2+30x+9 64 + 48x + 9x^2 = 9x^2 + 30x + 9

Cancel the 9x2 9x^2 terms from both sides:

64+48x=30x+9 64 + 48x = 30x + 9

Subtract 30x 30x from both sides to isolate the terms:

64+48x30x=9 64 + 48x - 30x = 9

64+18x=9 64 + 18x = 9

Subtract 64 from both sides:

18x=964 18x = 9 - 64

18x=55 18x = -55

Divide both sides by 18 to solve for x x :

x=5518 x = \frac{-55}{18}

Simplifying, this gives:

x=3118 x = -3 \frac{1}{18}

The solution to the problem is x=3118 x = -3 \frac{1}{18} , which matches choice 3.

3

Final Answer

3118 -3\frac{1}{18}

Key Points to Remember

Essential concepts to master this topic
  • Identity: Use a2b2=(ab)(a+b) a^2 - b^2 = (a-b)(a+b) to simplify equations
  • Technique: (5x+3)2(4x)2=(x+3)(9x+3) (5x+3)^2 - (4x)^2 = (x+3)(9x+3) factoring first
  • Check: Substitute x=3118 x = -3\frac{1}{18} back into original equation ✓

Common Mistakes

Avoid these frequent errors
  • Expanding all squares before using difference of squares identity
    Don't expand (5x+3)2(4x)2 (5x+3)^2 - (4x)^2 individually = 25x2+30x+916x2 25x^2 + 30x + 9 - 16x^2 creates unnecessary complexity! This makes the algebra much harder and increases error chances. Always recognize and apply a2b2=(ab)(a+b) a^2 - b^2 = (a-b)(a+b) first.

Practice Quiz

Test your knowledge with interactive questions

Choose the expression that has the same value as the following:

\( (x+y)^2 \)

FAQ

Everything you need to know about this question

When should I use the difference of squares formula?

+

Use a2b2=(ab)(a+b) a^2 - b^2 = (a-b)(a+b) whenever you see two squared terms being subtracted, like (5x+3)2(4x)2 (5x+3)^2 - (4x)^2 . This simplifies the problem much faster than expanding!

Why didn't we expand the left side using difference of squares?

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The left side (8+3x)2 (8+3x)^2 is just one square term, not a difference. The difference of squares formula only works when you have subtraction between two squares.

How do I factor (x+3)(9x+3) correctly?

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Use the FOIL method: First terms: x9x=9x2 x \cdot 9x = 9x^2 , Outer: x3=3x x \cdot 3 = 3x , Inner: 39x=27x 3 \cdot 9x = 27x , Last: 33=9 3 \cdot 3 = 9 . Result: 9x2+30x+9 9x^2 + 30x + 9

What if I get a mixed number as my answer?

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Mixed numbers like 3118 -3\frac{1}{18} are perfectly valid! Convert to check: 3118=5518 -3\frac{1}{18} = \frac{-55}{18} . Always verify by substituting back into the original equation.

Can I solve this by taking square roots of both sides?

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No! Taking square roots only works when you have (expression)2=number (expression)^2 = number . Here we have (8+3x)2=(5x+3)2(4x)2 (8+3x)^2 = (5x+3)^2 - (4x)^2 , so the right side isn't just a number.

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