Solve (x+4)² - 1: Finding Y-Axis Intersection Points

To solve this problem, we'll follow these steps:

• Step 1: Identify the equation of the function $y = (x+4)^2 - 1$.

• Step 2: Since we're finding the intersection with the Y-axis, set $x = 0$.

• Step 3: Substitute $x = 0$ into the equation and solve for $y$.

Now, let's work through each step:

Step 1: The equation of the function is already given as $y = (x+4)^2 - 1$.

Step 2: To find the Y-intercept, let $x = 0$.

Step 3: Substitute $x = 0$ into the equation:

$\begin{aligned} y &= (0 + 4)^2 - 1 \\ &= 4^2 - 1 \\ &= 16 - 1 \\ &= 15 \end{aligned}$

Therefore, the intersection with the Y-axis is at $(0, 15)$.