Find the intersection of the function
With the Y
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Find the intersection of the function
With the Y
The problem asks us to find where the parabola given by intersects the y-axis. The intersection with the y-axis occurs where . Let's find the value of by substituting into the equation:
Simplify inside the parentheses:
Calculate :
Subtract 4 from 9:
Thus, the intersection of the function with the y-axis occurs at the point .
The correct answer from the choices provided is .
Which equation represents the function:
\( y=x^2 \)
moved 2 spaces to the right
and 5 spaces upwards.
The y-axis is where x = 0 on the coordinate plane. Any point on the y-axis has coordinates (0, y). So to find where your function crosses the y-axis, substitute x = 0!
Y-intercept: Set x = 0, find y-value (where curve crosses y-axis)
X-intercept: Set y = 0, solve for x (where curve crosses x-axis)
The y-intercept is a point on the coordinate plane! It needs both coordinates: (x,y) = (0,5). The number 5 alone is just the y-coordinate.
Yes! Every function passes the vertical line test, so it can only cross the y-axis (the line x = 0) at most once. Most functions have exactly one y-intercept.
Substitute back: . Since we get y = 5 when x = 0, the point (0,5) is correct!
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