Understanding Absolute Value Inequality: |x-5| > -11

Absolute Value Inequalities with Negative Numbers

Given:

x5>11 \left|x-5\right|>-11

Which of the following statements is necessarily true?

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1

Understand the problem

Given:

x5>11 \left|x-5\right|>-11

Which of the following statements is necessarily true?

2

Step-by-step solution

The absolute value expression x5>11 \left| x - 5 \right| > -11 inherently suggests that for any real number x x , the inequality holds.

Since the absolute value of any expression is always non-negative and 11-11 is negative, the condition x5>11 \left| x - 5 \right| > -11 is always satisfied regardless of the choice of x x .

Thus, there is no specific limitation or exceptional circumstance that confines x x to any particular subset of the real numbers.

This implies that no particular statement about x x being greater, less, or constrained to a specific domain can be justified. Therefore, the notion of any statement being "necessarily true" in the conventional sense of constraining x x does not apply.

The correct answer, therefore, is: all x x .

3

Final Answer

all x x

Key Points to Remember

Essential concepts to master this topic
  • Rule: Absolute value is always non-negative (≥ 0)
  • Technique: Since |x-5| ≥ 0 and -11 < 0, inequality is always true
  • Check: Test any value: |2-5| = 3 > -11 ✓

Common Mistakes

Avoid these frequent errors
  • Trying to solve |x-5| > -11 like a normal absolute value inequality
    Don't set up |x-5| = -11 or create cases like x-5 > -11 and x-5 < 11 = wrong approach! This treats -11 as positive and creates false restrictions. Always recognize that absolute value > negative number means all real numbers satisfy it.

Practice Quiz

Test your knowledge with interactive questions

Given:

\( \left|2x-1\right|>-10 \)

Which of the following statements is necessarily true?

FAQ

Everything you need to know about this question

Why does |x-5| > -11 work for all values of x?

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The absolute value of any expression is always zero or positive. Since x50 |x-5| ≥ 0 and 11<0 -11 < 0 , we always have x5>11 |x-5| > -11 !

What if the inequality was |x-5| < -11 instead?

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That would have no solution! Since absolute values are never negative, x5 |x-5| can never be less than -11. The solution set would be empty.

How is this different from |x-5| > 11?

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With x5>11 |x-5| > 11 , you need to solve two cases: x-5 > 11 or x-5 < -11, giving x > 16 or x < -6. But with a negative number on the right, all values work!

Can I just ignore the absolute value signs?

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Never ignore absolute value signs! They're crucial for understanding the problem. In this case, they help us recognize that we're comparing a non-negative value to a negative number.

How do I check my answer when the solution is 'all x'?

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Pick any value for x and substitute it in! Try x = 0: 05=5>11 |0-5| = 5 > -11 ✓. Try x = 100: 1005=95>11 |100-5| = 95 > -11 ✓. Every value works!

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