Examples with solutions for Addition: Addition of 2-digit and 1-digit numbers with the regrouping of tens

Exercise #1

Determine the numerical value of the {\triangle}

5+=10 5+{\triangle}=10

Step-by-Step Solution

To solve the problem, we will determine the value of \triangle in the equation 5+=10 5 + \triangle = 10 .

Here are the steps:

  • Step 1: Write down the original equation:

5+=10 5 + \triangle = 10

  • Step 2: Isolate \triangle by subtracting 5 5 from both sides of the equation:

=105 \triangle = 10 - 5

  • Step 3: Calculate the result:

=5 \triangle = 5

Thus, the numerical value of the triangle symbol is 5 5 .

Therefore, the solution to the problem is 5 5 .

Answer

5 5

Exercise #2

Determine the numerical value of the triangle:

+7=10 \triangle+7=10

Step-by-Step Solution

To determine the value of the triangle, we begin with the equation given:

+7=10 \triangle + 7 = 10

We want to isolate \triangle . To do so, we subtract 7 from both sides of the equation:

+77=107 \triangle + 7 - 7 = 10 - 7

This simplifies to:

=3 \triangle = 3

Thus, the value of the triangle is 3 3 .

Answer

3 3

Exercise #3

Determine the numerical value of the triangle:

If

8+=30 8+\triangle=30

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Set up the equation.
  • Step 2: Isolate the triangle symbol using subtraction.
  • Step 3: Calculate the numerical value of the triangle.

Now, let's work through each step:

Step 1: Set up the equation:

We start with the equation 8+=308 + \triangle = 30.

Step 2: Isolate the triangle symbol:

To find \triangle, we subtract 88 from both sides of the equation:

=308 \triangle = 30 - 8

Step 3: Calculate the numerical value of the triangle:

Performing the subtraction gives us:

=22 \triangle = 22

Therefore, the solution to the problem is =22 \triangle = 22 .

Answer

22 22

Exercise #4

Determine the numerical value of the triangle:

78+=80 78+\triangle=80

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Recognize the format of the provided equation.
  • Apply the appropriate arithmetic operation to isolate \triangle.
  • Perform the necessary calculations.

Now, let's work through each step:
Step 1: The given equation is 78+=80 78 + \triangle = 80 . We are tasked with finding the value of \triangle.
Step 2: To find \triangle, rearrange the equation to solve for \triangle:
=8078\triangle = 80 - 78.
Step 3: Subtract the known value from the total to isolate \triangle:
=8078=2\triangle = 80 - 78 = 2.

Hence, the solution to the problem is =2\triangle = 2.

Answer

2 2

Exercise #5

Determine the numerical value of the triangle:

If

8+=40 8+\triangle=40

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the given information

  • Step 2: Rearrange the equation to solve for \triangle

  • Step 3: Perform the subtraction to find \triangle

Now, let's work through each step:
Step 1: The problem gives us the equation 8+=40 8 + \triangle = 40 . We need to find the value of \triangle .
Step 2: To isolate \triangle , we subtract 8 from both sides of the equation: =408 \triangle = 40 - 8 .
Step 3: Perform the subtraction, 408=32 40 - 8 = 32 .

Therefore, the solution to the problem is =32 \triangle = 32 .

Answer

32 32

Exercise #6

Determine the numerical value of the triangle:

+79=80 \triangle+79=80

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Rewrite the given equation by subtracting 79 from both sides.
  • Step 2: Simplify the result to isolate and determine the value of the triangle ()(\triangle).

Now, let's work through each step:
Step 1: We start with the equation +79=80 \triangle + 79 = 80 . To isolate \triangle, subtract 79 from both sides:
+7979=8079 \triangle + 79 - 79 = 80 - 79 .

Step 2: Simplify the result:
=1 \triangle = 1 .

Therefore, the numerical value of the triangle is =1 \triangle = 1 . This corresponds with choice 3.

Answer

1 1

Exercise #7

Determine the numerical value of the triangle:

41+=50 41+\triangle=50

Step-by-Step Solution

To determine the value of the triangle, we will solve the equation 41+=50 41 + \triangle = 50 .

Let's solve it step by step:

  • Step 1: Start with the equation: 41+=50 41 + \triangle = 50 .
  • Step 2: To isolate \triangle, subtract 41 from both sides:
  • Step 3: 41+41=5041 41 + \triangle - 41 = 50 - 41 .
  • Step 4: This simplifies to =9\triangle = 9.

Therefore, the solution to the problem is =9 \triangle = 9 .

Answer

9 9

Exercise #8

Determine the numerical value of the triangle:

33+=40 33+\triangle=40

Step-by-Step Solution

To solve the equation 33+=40 33 + \triangle = 40 , we will follow these steps:

  • Step 1: Write down the equation: 33+=40 33 + \triangle = 40 .
  • Step 2: Subtract 33 from both sides to isolate \triangle :
  • =4033 \triangle = 40 - 33 .
  • Step 3: Perform the subtraction: 4033=7 40 - 33 = 7 .

Therefore, the numerical value of the triangle \triangle is 7 7 .

Accordingly, the correct answer choice is 7 7 , which matches choice 4.

Answer

7 7

Exercise #9

Determine the numerical value of the triangle:

56+=60 56+\triangle=60

Step-by-Step Solution

To solve this problem, we'll use basic arithmetic involving subtraction:

  • Step 1: Understand the equation 56+=6056 + \triangle = 60.
  • Step 2: To isolate \triangle, subtract 56 from 60.
  • Step 3: Calculate 605660 - 56, which gives us the value of \triangle.

Now, let's work through each step:

Step 1: We recognize that we need \triangle such that 56+=6056 + \triangle = 60.

Step 2: Subtract 56 from 60: 605660 - 56.

Step 3: Perform the calculation: 6056=460 - 56 = 4.

Therefore, the value of the triangle \triangle is 44.

Answer

4 4