Examples with solutions for Addition: Shapes instead of numbers

Exercise #1

If

=12 \colorbox{yellow}\\=12

Solve the following addition problem:

23+= 23+ \colorbox{yellow}\\=

Step-by-Step Solution

To solve this problem, we will follow these steps:

  • Step 1: Recognize that the unknown represented by the yellow box is given as 12.
  • Step 2: Set up the addition equation using the information given: 23+12 23 + 12 .
  • Step 3: Perform the addition.
  • Step 4: Match the result with one of the provided choices.

Now, let's perform the calculations:
Step 1: Interpret yellow box=12 \text{yellow box} = 12 as 12 12 .
Step 2: The expression we need to solve is 23+12 23 + 12 .
Step 3: Calculate the sum:
23+12=35 23 + 12 = 35 .

We find that the sum of 23 and 12 is 35.

Therefore, the solution to the problem is 35 35 , which corresponds to choice number 2 in the given options.

Answer

35 35

Exercise #2

If:

=12 \colorbox{yellow}\\=12

Solve the following addition problem:

+14= \colorbox{yellow}\\+14=

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Substitute the symbol with the given number 1212.
  • Step 2: Add this number to 1414.

Now, let's work through each step:

Step 1: According to the problem, the symbol inside the yellow box equals 1212. This means wherever we see this symbol, we can replace it with 1212.
Step 2: We need to solve 12+1412 + 14. Let's perform this calculation:

12+14=2612 + 14 = 26

Therefore, the correct solution to the problem is 2626.

Answer

26 26

Exercise #3

If:

=12 \colorbox{yellow}\\=12

Solve the following addition problem:

+50= \colorbox{yellow}\\+50=

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the value of the yellow box.
  • Step 2: Perform the addition with the given value.
  • Step 3: Verify the result is among the provided choices.

Now, let's work through each step:
Step 1: The problem states the yellow box is equal to 12 12 .
Step 2: Add 12 12 to 50 50 :

12+50=62 12 + 50 = 62

Step 3: Look at the possible answer choices:

  • Choice 1: 62 62
  • Choice 2: 52 52
  • Choice 3: 72 72
  • Choice 4: 54 54
The correct choice is clearly 62 62 , which matches our computed result.

Therefore, the solution to the problem is 62 62 .

Answer

62 62

Exercise #4

If:

=12 \colorbox{yellow}\\=12

Solve the following addition problem:

+30= \colorbox{yellow}\\+30=

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Recognize that the yellow shape represents the number 12.
  • Step 2: Replace the shape in the equation with its numeric value.
  • Step 3: Perform the addition.

Now, let's work through these steps:
Step 1: The problem states that the yellow shape is equivalent to 12 12 .
Step 2: We replace the yellow shape with 12 12 in the addition equation.
Step 3: Solve the equation 12+30=42 12 + 30 = 42 . This addition gives us the solution.

Therefore, the solution to the problem is 42 42 .

Answer

42 42

Exercise #5

Determine the numerical value of the {\triangle}

5+=10 5+{\triangle}=10

Step-by-Step Solution

To solve the problem, we will determine the value of \triangle in the equation 5+=10 5 + \triangle = 10 .

Here are the steps:

  • Step 1: Write down the original equation:

5+=10 5 + \triangle = 10

  • Step 2: Isolate \triangle by subtracting 5 5 from both sides of the equation:

=105 \triangle = 10 - 5

  • Step 3: Calculate the result:

=5 \triangle = 5

Thus, the numerical value of the triangle symbol is 5 5 .

Therefore, the solution to the problem is 5 5 .

Answer

5 5

Exercise #6

Determine the numerical value of the triangle:

8+=68 8+{\triangle}=68

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Recognize the given equation 8+=68 8 + \triangle = 68 .
  • Step 2: To isolate \triangle , subtract 8 from both sides of the equation.

Now, let's work through each step:
Step 1: We initially have the equation 8+=68 8 + \triangle = 68 .
Step 2: Subtract 8 from both sides to find \triangle :

=688 \triangle = 68 - 8

This calculation gives us:

=60 \triangle = 60

Therefore, the numerical value of the triangle is 60 60 .

Answer

60 60

Exercise #7

Determine the numerical value of the triangle:

+79=89 {\triangle}+79=89

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the equation given as +79=89 \triangle + 79 = 89 .
  • Step 2: Solve for the unknown variable \triangle.

Now, let's work through each step:
Step 1: Observe that the equation is structured as an addition problem with an unknown symbol \triangle.
Step 2: To isolate \triangle, perform the subtraction 897989 - 79 on the right side of the equation:

=8979 \triangle = 89 - 79

Perform the subtraction:

8979=10 89 - 79 = 10

Thus, the numerical value of the triangle (\triangle) is 10 10 .

Answer

10 10

Exercise #8

Determine the numerical value of the triangle:

6+=26 6+{\triangle}=26

Step-by-Step Solution

To solve the equation 6+=26 6 + \triangle = 26 , we seek the value of \triangle . We can easily obtain this by isolating \triangle on one side of the equation.

We employ the subtraction method to isolate \triangle :

  • Subtract 6 from both sides of the equation:
=266\triangle = 26 - 6

Perform the calculation:

=20 \triangle = 20

Thus, the numerical value of the triangle is 20 20 .

Answer

20 20

Exercise #9

If

=7 \circ=7

Solve the following addition problem:

+21= \circ+21=

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the number represented by the symbol \circ .
  • Step 2: Substitute the symbol \circ with the number 7.
  • Step 3: Perform the addition of 7 and 21.

Now, let's work through each step:
Step 1: Identify =7 \circ = 7 from the problem statement.
Step 2: Substitute the value 7 for \circ in +21 \circ + 21 , so we have 7+21 7 + 21 .
Step 3: Add 7 and 21 to get 28.

Therefore, the solution to the problem is 28 28 .

Answer

28 28

Exercise #10

Determine the numerical value of the triangle:

30+=38 30+{\triangle}=38

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the known numbers in the equation.
  • Step 2: Rearrange the equation to solve for the unknown value.
  • Step 3: Calculate using basic subtraction.

Now, let's work through each step:
Step 1: The known numbers in the equation are 3030 and 3838. We need to find \triangle in 30+=3830 + \triangle = 38.
Step 2: Rearrange the equation to isolate \triangle: =3830 \triangle = 38 - 30 .
Step 3: Calculate the difference: =8 \triangle = 8 .

Therefore, the value of the triangle is 8 8 .

Answer

8 8

Exercise #11

If:

=7 \circ=7

Solve the following addition problem:

60+= 60+\circ=

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the given information
  • Step 2: Substitute the value of \circ and perform addition

Now, let's work through each step:
Step 1: The problem states that =7 \circ = 7 .
Step 2: Substitute the value into the equation 60+ 60 + \circ to get 60+7 60 + 7 .
Perform the addition: 60+7=67 60 + 7 = 67 .

Therefore, the solution to the problem is 67 67 .

Answer

67 67

Exercise #12

If:

=7 \circ=7

Solve the following addition problem:

42+= 42+\circ=

Step-by-Step Solution

Let's solve the problem step-by-step:

  • Step 1: Identify the substitution needed.
    We are given that =7 \circ = 7 . Thus, we need to solve 42+ 42 + \circ by substituting \circ with 7.

  • Step 2: Substitute the value into the addition problem.
    The expression becomes 42+7 42 + 7 .

  • Step 3: Perform the addition.
    To find 42+7 42 + 7 , add the two numbers: 42+7=49 42 + 7 = 49

Thus, the solution to the problem is 49 49 .

Correct Answer Choice: 49 49

Answer

49 49

Exercise #13

Determine the numerical value of the triangle:

+25=30 \triangle+25=30

Step-by-Step Solution

To solve this problem, we need to find the value represented by the triangle symbol in the equation +25=30 \triangle + 25 = 30 . This involves a straightforward algebraic process.

First, we want to isolate the triangle by removing the 25 that is added to it. To do this, we will subtract 25 from both sides of the equation:

  • +25=30 \triangle + 25 = 30
  • Subtract 25 from both sides: +2525=3025 \triangle + 25 - 25 = 30 - 25

Simplifying both sides, we have:

  • =3025 \triangle = 30 - 25
  • =5 \triangle = 5

Therefore, the value of the triangle is 5 5 .

Answer

5 5

Exercise #14

Determine the numerical value of the triangle:

45+=50 45+\triangle=50

Step-by-Step Solution

Let's solve the problem step by step:

  • Step 1: Start with the equation provided: 45+=50 45 + \triangle = 50 .

  • Step 2: To solve for \triangle, isolate it by subtracting 45 from both sides of the equation to maintain equality.

  • This subtraction gives: =5045\triangle = 50 - 45.

  • Step 3: Perform the subtraction on the right-hand side: 5045=550 - 45 = 5.

Thus, the numerical value of the triangle (\triangle) is 5 5 .

Answer

5 5

Exercise #15

Determine the numerical value of the triangle:

+7=10 \triangle+7=10

Step-by-Step Solution

To determine the value of the triangle, we begin with the equation given:

+7=10 \triangle + 7 = 10

We want to isolate \triangle . To do so, we subtract 7 from both sides of the equation:

+77=107 \triangle + 7 - 7 = 10 - 7

This simplifies to:

=3 \triangle = 3

Thus, the value of the triangle is 3 3 .

Answer

3 3

Exercise #16

Determine the numerical value of the triangle:

If

8+=30 8+\triangle=30

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Set up the equation.
  • Step 2: Isolate the triangle symbol using subtraction.
  • Step 3: Calculate the numerical value of the triangle.

Now, let's work through each step:

Step 1: Set up the equation:

We start with the equation 8+=308 + \triangle = 30.

Step 2: Isolate the triangle symbol:

To find \triangle, we subtract 88 from both sides of the equation:

=308 \triangle = 30 - 8

Step 3: Calculate the numerical value of the triangle:

Performing the subtraction gives us:

=22 \triangle = 22

Therefore, the solution to the problem is =22 \triangle = 22 .

Answer

22 22

Exercise #17

Determine the numerical value of the triangle:

78+=80 78+\triangle=80

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Recognize the format of the provided equation.
  • Apply the appropriate arithmetic operation to isolate \triangle.
  • Perform the necessary calculations.

Now, let's work through each step:
Step 1: The given equation is 78+=80 78 + \triangle = 80 . We are tasked with finding the value of \triangle.
Step 2: To find \triangle, rearrange the equation to solve for \triangle:
=8078\triangle = 80 - 78.
Step 3: Subtract the known value from the total to isolate \triangle:
=8078=2\triangle = 80 - 78 = 2.

Hence, the solution to the problem is =2\triangle = 2.

Answer

2 2

Exercise #18

Determine the numerical value of the triangle:

If

8+=40 8+\triangle=40

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the given information

  • Step 2: Rearrange the equation to solve for \triangle

  • Step 3: Perform the subtraction to find \triangle

Now, let's work through each step:
Step 1: The problem gives us the equation 8+=40 8 + \triangle = 40 . We need to find the value of \triangle .
Step 2: To isolate \triangle , we subtract 8 from both sides of the equation: =408 \triangle = 40 - 8 .
Step 3: Perform the subtraction, 408=32 40 - 8 = 32 .

Therefore, the solution to the problem is =32 \triangle = 32 .

Answer

32 32

Exercise #19

Determine the numerical value of the triangle:

+79=80 \triangle+79=80

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Rewrite the given equation by subtracting 79 from both sides.
  • Step 2: Simplify the result to isolate and determine the value of the triangle ()(\triangle).

Now, let's work through each step:
Step 1: We start with the equation +79=80 \triangle + 79 = 80 . To isolate \triangle, subtract 79 from both sides:
+7979=8079 \triangle + 79 - 79 = 80 - 79 .

Step 2: Simplify the result:
=1 \triangle = 1 .

Therefore, the numerical value of the triangle is =1 \triangle = 1 . This corresponds with choice 3.

Answer

1 1

Exercise #20

Determine the numerical value of the triangle:

41+=50 41+\triangle=50

Step-by-Step Solution

To determine the value of the triangle, we will solve the equation 41+=50 41 + \triangle = 50 .

Let's solve it step by step:

  • Step 1: Start with the equation: 41+=50 41 + \triangle = 50 .
  • Step 2: To isolate \triangle, subtract 41 from both sides:
  • Step 3: 41+41=5041 41 + \triangle - 41 = 50 - 41 .
  • Step 4: This simplifies to =9\triangle = 9.

Therefore, the solution to the problem is =9 \triangle = 9 .

Answer

9 9