Examples with solutions for Addition: Shapes instead of numbers

Exercise #1

If:

=7 \circ=7

Solve the following addition problem:

42+= 42+\circ=

Step-by-Step Solution

Let's solve the problem step-by-step:

  • Step 1: Identify the substitution needed.
    We are given that =7 \circ = 7 . Thus, we need to solve 42+ 42 + \circ by substituting \circ with 7.

  • Step 2: Substitute the value into the addition problem.
    The expression becomes 42+7 42 + 7 .

  • Step 3: Perform the addition.
    To find 42+7 42 + 7 , add the two numbers: 42+7=49 42 + 7 = 49

Thus, the solution to the problem is 49 49 .

Correct Answer Choice: 49 49

Answer

49 49

Exercise #2

Determine the numerical value of the triangle:

45+=50 45+\triangle=50

Step-by-Step Solution

Let's solve the problem step by step:

  • Step 1: Start with the equation provided: 45+=50 45 + \triangle = 50 .

  • Step 2: To solve for \triangle, isolate it by subtracting 45 from both sides of the equation to maintain equality.

  • This subtraction gives: =5045\triangle = 50 - 45.

  • Step 3: Perform the subtraction on the right-hand side: 5045=550 - 45 = 5.

Thus, the numerical value of the triangle (\triangle) is 5 5 .

Answer

5 5

Exercise #3

Determine the numerical value of the triangle:

+7=10 \triangle+7=10

Step-by-Step Solution

To determine the value of the triangle, we begin with the equation given:

+7=10 \triangle + 7 = 10

We want to isolate \triangle . To do so, we subtract 7 from both sides of the equation:

+77=107 \triangle + 7 - 7 = 10 - 7

This simplifies to:

=3 \triangle = 3

Thus, the value of the triangle is 3 3 .

Answer

3 3

Exercise #4

Determine the numerical value of the triangle:

41+=50 41+\triangle=50

Step-by-Step Solution

To determine the value of the triangle, we will solve the equation 41+=50 41 + \triangle = 50 .

Let's solve it step by step:

  • Step 1: Start with the equation: 41+=50 41 + \triangle = 50 .
  • Step 2: To isolate \triangle, subtract 41 from both sides:
  • Step 3: 41+41=5041 41 + \triangle - 41 = 50 - 41 .
  • Step 4: This simplifies to =9\triangle = 9.

Therefore, the solution to the problem is =9 \triangle = 9 .

Answer

9 9

Exercise #5

Determine the numerical value of the triangle:

33+=40 33+\triangle=40

Step-by-Step Solution

To solve the equation 33+=40 33 + \triangle = 40 , we will follow these steps:

  • Step 1: Write down the equation: 33+=40 33 + \triangle = 40 .
  • Step 2: Subtract 33 from both sides to isolate \triangle :
  • =4033 \triangle = 40 - 33 .
  • Step 3: Perform the subtraction: 4033=7 40 - 33 = 7 .

Therefore, the numerical value of the triangle \triangle is 7 7 .

Accordingly, the correct answer choice is 7 7 , which matches choice 4.

Answer

7 7

Exercise #6

Determine the numerical value of the triangle:

6+=26 6+{\triangle}=26

Step-by-Step Solution

To solve the equation 6+=26 6 + \triangle = 26 , we seek the value of \triangle . We can easily obtain this by isolating \triangle on one side of the equation.

We employ the subtraction method to isolate \triangle :

  • Subtract 6 from both sides of the equation:
=266\triangle = 26 - 6

Perform the calculation:

=20 \triangle = 20

Thus, the numerical value of the triangle is 20 20 .

Answer

20 20

Exercise #7

Determine the numerical value of the {\triangle}

5+=10 5+{\triangle}=10

Step-by-Step Solution

To solve the problem, we will determine the value of \triangle in the equation 5+=10 5 + \triangle = 10 .

Here are the steps:

  • Step 1: Write down the original equation:

5+=10 5 + \triangle = 10

  • Step 2: Isolate \triangle by subtracting 5 5 from both sides of the equation:

=105 \triangle = 10 - 5

  • Step 3: Calculate the result:

=5 \triangle = 5

Thus, the numerical value of the triangle symbol is 5 5 .

Therefore, the solution to the problem is 5 5 .

Answer

5 5

Exercise #8

Determine the numerical value of the triangle:

If

8+=40 8+\triangle=40

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the given information

  • Step 2: Rearrange the equation to solve for \triangle

  • Step 3: Perform the subtraction to find \triangle

Now, let's work through each step:
Step 1: The problem gives us the equation 8+=40 8 + \triangle = 40 . We need to find the value of \triangle .
Step 2: To isolate \triangle , we subtract 8 from both sides of the equation: =408 \triangle = 40 - 8 .
Step 3: Perform the subtraction, 408=32 40 - 8 = 32 .

Therefore, the solution to the problem is =32 \triangle = 32 .

Answer

32 32

Exercise #9

Determine the numerical value of the triangle:

78+=80 78+\triangle=80

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Recognize the format of the provided equation.
  • Apply the appropriate arithmetic operation to isolate \triangle.
  • Perform the necessary calculations.

Now, let's work through each step:
Step 1: The given equation is 78+=80 78 + \triangle = 80 . We are tasked with finding the value of \triangle.
Step 2: To find \triangle, rearrange the equation to solve for \triangle:
=8078\triangle = 80 - 78.
Step 3: Subtract the known value from the total to isolate \triangle:
=8078=2\triangle = 80 - 78 = 2.

Hence, the solution to the problem is =2\triangle = 2.

Answer

2 2

Exercise #10

Determine the numerical value of the triangle:

+79=89 {\triangle}+79=89

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the equation given as +79=89 \triangle + 79 = 89 .
  • Step 2: Solve for the unknown variable \triangle.

Now, let's work through each step:
Step 1: Observe that the equation is structured as an addition problem with an unknown symbol \triangle.
Step 2: To isolate \triangle, perform the subtraction 897989 - 79 on the right side of the equation:

=8979 \triangle = 89 - 79

Perform the subtraction:

8979=10 89 - 79 = 10

Thus, the numerical value of the triangle (\triangle) is 10 10 .

Answer

10 10

Exercise #11

If:

=7 \circ=7

Solve the following addition problem:

60+= 60+\circ=

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the given information
  • Step 2: Substitute the value of \circ and perform addition

Now, let's work through each step:
Step 1: The problem states that =7 \circ = 7 .
Step 2: Substitute the value into the equation 60+ 60 + \circ to get 60+7 60 + 7 .
Perform the addition: 60+7=67 60 + 7 = 67 .

Therefore, the solution to the problem is 67 67 .

Answer

67 67

Exercise #12

Determine the numerical value of the triangle:

30+=38 30+{\triangle}=38

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the known numbers in the equation.
  • Step 2: Rearrange the equation to solve for the unknown value.
  • Step 3: Calculate using basic subtraction.

Now, let's work through each step:
Step 1: The known numbers in the equation are 3030 and 3838. We need to find \triangle in 30+=3830 + \triangle = 38.
Step 2: Rearrange the equation to isolate \triangle: =3830 \triangle = 38 - 30 .
Step 3: Calculate the difference: =8 \triangle = 8 .

Therefore, the value of the triangle is 8 8 .

Answer

8 8

Exercise #13

If

=7 \circ=7

Solve the following addition problem:

+21= \circ+21=

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the number represented by the symbol \circ .
  • Step 2: Substitute the symbol \circ with the number 7.
  • Step 3: Perform the addition of 7 and 21.

Now, let's work through each step:
Step 1: Identify =7 \circ = 7 from the problem statement.
Step 2: Substitute the value 7 for \circ in +21 \circ + 21 , so we have 7+21 7 + 21 .
Step 3: Add 7 and 21 to get 28.

Therefore, the solution to the problem is 28 28 .

Answer

28 28

Exercise #14

If:

=12 \colorbox{yellow}\\=12

Solve the following addition problem:

+50= \colorbox{yellow}\\+50=

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the value of the yellow box.
  • Step 2: Perform the addition with the given value.
  • Step 3: Verify the result is among the provided choices.

Now, let's work through each step:
Step 1: The problem states the yellow box is equal to 12 12 .
Step 2: Add 12 12 to 50 50 :

12+50=62 12 + 50 = 62

Step 3: Look at the possible answer choices:

  • Choice 1: 62 62
  • Choice 2: 52 52
  • Choice 3: 72 72
  • Choice 4: 54 54
The correct choice is clearly 62 62 , which matches our computed result.

Therefore, the solution to the problem is 62 62 .

Answer

62 62

Exercise #15

If:

=12 \colorbox{yellow}\\=12

Solve the following addition problem:

+30= \colorbox{yellow}\\+30=

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Recognize that the yellow shape represents the number 12.
  • Step 2: Replace the shape in the equation with its numeric value.
  • Step 3: Perform the addition.

Now, let's work through these steps:
Step 1: The problem states that the yellow shape is equivalent to 12 12 .
Step 2: We replace the yellow shape with 12 12 in the addition equation.
Step 3: Solve the equation 12+30=42 12 + 30 = 42 . This addition gives us the solution.

Therefore, the solution to the problem is 42 42 .

Answer

42 42

Exercise #16

Determine the numerical value of the triangle:

8+=68 8+{\triangle}=68

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Recognize the given equation 8+=68 8 + \triangle = 68 .
  • Step 2: To isolate \triangle , subtract 8 from both sides of the equation.

Now, let's work through each step:
Step 1: We initially have the equation 8+=68 8 + \triangle = 68 .
Step 2: Subtract 8 from both sides to find \triangle :

=688 \triangle = 68 - 8

This calculation gives us:

=60 \triangle = 60

Therefore, the numerical value of the triangle is 60 60 .

Answer

60 60

Exercise #17

Determine the numerical value of the triangle:

+79=80 \triangle+79=80

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Rewrite the given equation by subtracting 79 from both sides.
  • Step 2: Simplify the result to isolate and determine the value of the triangle ()(\triangle).

Now, let's work through each step:
Step 1: We start with the equation +79=80 \triangle + 79 = 80 . To isolate \triangle, subtract 79 from both sides:
+7979=8079 \triangle + 79 - 79 = 80 - 79 .

Step 2: Simplify the result:
=1 \triangle = 1 .

Therefore, the numerical value of the triangle is =1 \triangle = 1 . This corresponds with choice 3.

Answer

1 1

Exercise #18

Determine the numerical value of the triangle:

If

8+=30 8+\triangle=30

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Set up the equation.
  • Step 2: Isolate the triangle symbol using subtraction.
  • Step 3: Calculate the numerical value of the triangle.

Now, let's work through each step:

Step 1: Set up the equation:

We start with the equation 8+=308 + \triangle = 30.

Step 2: Isolate the triangle symbol:

To find \triangle, we subtract 88 from both sides of the equation:

=308 \triangle = 30 - 8

Step 3: Calculate the numerical value of the triangle:

Performing the subtraction gives us:

=22 \triangle = 22

Therefore, the solution to the problem is =22 \triangle = 22 .

Answer

22 22

Exercise #19

If:

=12 \colorbox{yellow}\\=12

Solve the following addition problem:

+14= \colorbox{yellow}\\+14=

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Substitute the symbol with the given number 1212.
  • Step 2: Add this number to 1414.

Now, let's work through each step:

Step 1: According to the problem, the symbol inside the yellow box equals 1212. This means wherever we see this symbol, we can replace it with 1212.
Step 2: We need to solve 12+1412 + 14. Let's perform this calculation:

12+14=2612 + 14 = 26

Therefore, the correct solution to the problem is 2626.

Answer

26 26

Exercise #20

Determine the numerical value of the triangle:

56+=60 56+\triangle=60

Step-by-Step Solution

To solve this problem, we'll use basic arithmetic involving subtraction:

  • Step 1: Understand the equation 56+=6056 + \triangle = 60.
  • Step 2: To isolate \triangle, subtract 56 from 60.
  • Step 3: Calculate 605660 - 56, which gives us the value of \triangle.

Now, let's work through each step:

Step 1: We recognize that we need \triangle such that 56+=6056 + \triangle = 60.

Step 2: Subtract 56 from 60: 605660 - 56.

Step 3: Perform the calculation: 6056=460 - 56 = 4.

Therefore, the value of the triangle \triangle is 44.

Answer

4 4