Long Division Practice Problems with Step-by-Step Solutions

To solve the division problem $90 \div 6$, follow these steps:

• Step 1: Identify the numbers involved, where 90 is the dividend and 6 is the divisor.
• Step 2: Divide 90 by 6 using long division.
• Step 3: Determine how many times 6 fits into 90 without exceeding it.

Let's perform the division:

90 divided by 6 equals 15, as 6 fits perfectly into 90 fifteen times (since $6 \times 15 = 90$). There is no remainder left over.

Given the multiple-choice options, the correct choice is: $15$.

This means that 6 goes into 90 exactly 15 times, matching Option 1 of the given choices.

To solve the problem of dividing 25 by 5, we follow these steps:

• Step 1: Identify the dividend and the divisor. In this case, the dividend is 25 and the divisor is 5.
• Step 2: Perform the division $25 \div 5$.

Now, let's execute the division:

Step 1: Divide 25 by 5. We ask ourselves how many times does 5 fit into 25.

Step 2: 5 goes into 25 exactly 5 times because $5 \times 5 = 25$ and there's no remainder.

Thus, we find that the quotient is 5.

Therefore, the answer to the problem is $5$.

To solve the problem of dividing 65 by 5, follow these steps:

• Step 1: Identify the dividend, which is 65, and the divisor, which is 5.
• Step 2: Perform the division operation $65 \div 5$.
• Step 3: Calculate the quotient by determining how many times 5 goes into 65 evenly.

Now, let's execute the division:
Step 1: We recognize that 65 is the number to be divided, and 5 is the divisor.
Step 2: Apply division: $65 \div 5 = 13$.
Since 65 divided by 5 yields a quotient of 13 without any remainder, we have found our solution.

Thus, the answer to the division problem is $13$.

To solve the problem $39 \div 3$, we will apply long division:

• Step 1: Set up the division problem.
  Write 39 inside the division bracket and 3 outside as the divisor.
• Step 2: Divide the first digit of the dividend by the divisor.
  Determine how many times 3 fits into 3 (the first digit of 39):
  3 fits into 3 exactly 1 time. Write 1 above the line.
• Step 3: Multiply and subtract.
  Multiply 3 (divisor) by the result from the previous step (1), giving 3.
  Subtract 3 from 3, resulting in 0.
• Step 4: Bring down the next digit of the dividend.
  Bring down 9 (the next digit from 39). The new number to consider is 9.
• Step 5: Divide the result by the divisor.
  Determine how many times 3 fits into 9: 3 fits into 9 exactly 3 times. Write 3 above the line.
• Step 6: Multiply and subtract again.
  Multiply 3 by 3, which gives 9. Subtract 9 from 9, resulting in 0.

The division process is complete with no remainder. The quotient is 13.

The final answer is $\boxed{13}$.

To solve this division problem, we will divide the number 48 by 4 and find the quotient.

The expression for this calculation is:

Let's perform the division:

• We start with the number 48.
• We divide 48 by 4. The question we are asking is: "How many times does 4 go into 48?"
• By calculating, we find that 4 fits into 48 exactly 12 times.

The steps can be broken down as follows:

• 4 goes into the first digit of 48 (4), 1 time.
• The remainder from this division is 0, bring down the next digit, which is 8.
• 4 goes into 8, 2 times (as 4 × 2 = 8).
• There is no remainder, confirming the division is complete.

Thus, the quotient of 48 divided by 4 is:

$12$

Therefore, the correct answer is 12, which corresponds to choice 4.