Vertical Multiplication Practice Problems & Worksheets

To solve this problem, we will multiply 24 by 7 using standard multiplication:

• Step 1: Multiply the unit digit of 24 by 7:
  $4 \times 7 = 28$. Write down 8 and carry over 2.
• Step 2: Multiply the tens digit of 24 by 7, then add the carry over:
  $2 \times 7 = 14$, and add the carried-over 2 to get 16.

The final result of these calculations is:
Since the unit's place is 8 and the ten's place is 16, our final answer is $168$.

Therefore, the solution to the problem is $168$.

To solve this problem, we'll follow these steps to multiply $77$ by $3$:

First, set up the numbers for vertical multiplication:

$\begin{array}{c} & 77 \\ \times & \,\,3 \\ \hline \end{array}$

• Step 1: Multiply the units:

$7 \times 3 = 21$

Write down $1$ and carry over $2$.

• Step 2: Multiply the tens:

$7 \times 3 = 21$

Add the carry-over $2$, resulting in $23$.

Write down $23$ as there are no more digits to multiply.

Combining both steps, we find the product of $77$ and $3$ is:

$\begin{array}{c} & 77 \\ \times & \,\,3 \\ \hline & 231 \\ \end{array}$

Therefore, the solution to the problem is $231$.

To solve this problem, we'll employ vertical multiplication.

Step 1: Set up the multiplication:
        $62$
×       $4$
      ---------

Step 2: Multiply each digit of 62 by 4. We start with the ones place, then the tens place.

• Multiply the ones digit: $2 \times 4 = 8$.
• Multiply the tens digit: $6 \times 4 = 24$.

Step 3: Consider the place value for each part of the calculation:
The result from multiplying the tens digit by 4 represents $240$ because it is $24 \times 10$.

Step 4: Add the two partial results:
         8
+ 240
      ---------
      248

Therefore, the solution to the problem is $248$.

To solve this problem, we will multiply $91$ by $3$ using standard multiplication techniques:

• Step 1: Multiply the unit digit of $91$ by $3$:
  $1 \times 3 = 3$.
• Step 2: Multiply the tens digit of $91$ by $3$:
  $9 \times 3 = 27$.
• Step 3: Place the result of $27$ correctly one digit to the left (because it's actually $90 \times 3$), which gives $270$.
• Step 4: Add the results from Step 1 and Step 3:
  $270 + 3 = 273$.

Therefore, the product of $91 \times 3$ is $273$.

To solve this problem, we'll follow these steps:

• Step 1: Identify the given numbers: $86$ and $3$.
• Step 2: Perform the vertical multiplication of $86$ by $3$.

Let's work through each step:

Step 1: We will multiply $86$ by $3$. The multiplication can be broken down as follows:

1. Multiply the units digit of $86$, which is $6$, by $3$:

$6 \times 3 = 18$

Write down $8$ and carry over $1$ to the next column (the tens place).

2. Multiply the tens digit of $86$, which is $8$, by $3$:

$8 \times 3 = 24$

Add the carried over $1$ to $24$:

$24 + 1 = 25$

Write down $25$. Since we're only multiplying a two-digit number by a one-digit number, our result directly follows:

Therefore, the solution to the problem is $258$.