Vertical Multiplication Practice Problems & Worksheets

We will solve the problem using direct multiplication of the two numbers, 30 and 4.

Steps:

• First, multiply the one's place of 30 by 4:
  $0 \times 4 = 0$

• Second, multiply the ten's place of 30 by 4:
  $3 \times 4 = 12$

• The result from the tens multiplication is over the magnitude of the number 30 (since it's in the tens place), so we already account for place by multiplying 3 by 4 directly forming a product 12, no tens digit carries from one's digit.

• Combine these results to get the total product:
  $0 + 120 = 120$

Therefore, the product of $30$ and $4$ is $\mathbf{120}$.

By referencing the multiple-choice options provided, the correct choice matches the calculation we performed and is choice 3: $120$.

To solve this multiplication problem, we will perform the following steps:

• Step 1: Write the two-digit number 19 as the sum of its place values: 19 = 10 + 9.
• Step 2: Multiply the first term (10) by 6: $10 \times 6 = 60$.
• Step 3: Multiply the second term (9) by 6: $9 \times 6 = 54$.
• Step 4: Add the results of the two multiplications: $60 + 54 = 114$.

Therefore, the product of 19 and 6 is $\textbf{114}$.

To solve this problem, we'll use long multiplication. Here's how to proceed step-by-step:

• Step 1: Begin with the multiplication of the units digit of 28, which is 8, by 5.
• Step 1 Calculation: $8 \times 5 = 40$. We write 0 in the units place and carry over 4.
• Step 2: Multiply the tens digit of 28, which is 2, by 5.
• Step 2 Calculation: $20 \times 5 = 100$.
• Step 3: Add the products from Step 1 and Step 2.
• Addition: $100 + 40 = 140$.

Therefore, the product of 28 and 5 is $140$.

To solve this problem, we will multiply 24 by 7 using standard multiplication:

• Step 1: Multiply the unit digit of 24 by 7:
  $4 \times 7 = 28$. Write down 8 and carry over 2.
• Step 2: Multiply the tens digit of 24 by 7, then add the carry over:
  $2 \times 7 = 14$, and add the carried-over 2 to get 16.

The final result of these calculations is:
Since the unit's place is 8 and the ten's place is 16, our final answer is $168$.

Therefore, the solution to the problem is $168$.

To solve this multiplication problem, follow these clear steps:

• Step 1: Align the numbers vertically (place 26 above 6), ensuring the digits are properly arranged by place value.
• Step 2: Begin multiplication with the unit digit of the bottom number (6). Multiply 6 by each digit in 26, starting from the right.

Now, let's perform the calculations:

Step 1: Multiply the units digit of 6 with the number 26:
- $6 \times 6 = 36$. Write 6 in the units place of the answer, and carry over the 3.
- Next, multiply $6 \times 2 = 12$. Then, add the carryover (3) to 12, resulting in 15.

Step 2: Write 15 next to the 6 in the result. Thus, the complete multiplication gives 156.

Therefore, the solution to the problem is $\boxed{156}$.