Vertical Subtraction - Examples, Exercises and Solutions

To solve this problem, we'll perform simple vertical subtraction for the numbers given, 15 and 4:

Step-by-step solution:

• Step 1: Write the numbers in a column, aligning the digits according to place value.
  
• Step 2: Start subtracting from the rightmost column (the ones column).
  In the ones column, subtract 4 from 5:$5 - 4 = 1$.
• Step 3: Move to the tens column. There is no subtraction to perform here since it's only $1 - 0$, which leaves the digit as is.

Thus, there is no borrowing needed because the digits in the minuend are sufficient to carry out the subtraction.

The result of the subtraction $15 - 4$ is $11$.

Therefore, the solution to the problem is $11$.

The correct multiple-choice answer is option 1: $11$.

To solve this problem, we'll perform vertical subtraction:

• Step 1: Write down the numbers vertically with the larger number (the minuend) on top:

$\begin{aligned} &27 \\ -& \\ &~~3 \\ &\underline{\phantom{776}} &\\ \end{aligned}$

• Step 2: Subtract the digits in the ones place: $7$ (from $27$) minus $3$ (from $3$) equals $4$.
• Step 3: Subtract the digits in the tens place: $2$ (from $27$) minus $0$ (no tens in $3$) equals $2$.

Therefore, the difference is $24$.

The solution to the problem is $24$, which corresponds to choice 2.

To solve this problem, we'll follow these steps:

• Step 1: Write the numbers vertically, with each digit aligned in their respective place value.

• Step 2: Begin subtracting starting from the rightmost column.

• Step 3: Move to the left, repeating the process for each subsequent column until finished.

Now, let's work through each step:
Step 1: Arrange the numbers vertically, aligning according to the decimal place.
 39
-   6
-----
Step 2: Start subtracting from the right. Subtract the ones place: $9 - 6 = 3$.
 39
-   6
-----
    3
Step 3: Since there is no need to borrow, move to the tens place:
The tens place comprises '3' from '39', as there is no corresponding digit above '6' to subtract from: $3 - 0 = 3$.
  39
-   6
-----
   33


Therefore, the solution to the problem is $33$.

To solve this problem, we'll follow these steps:

• Step 1: Align the numbers vertically by place value.

• Step 2: Subtract the units place.

• Step 3: Subtract the tens place if necessary.

Now, let's work through each step:
Step 1: Write the numbers 48 and 7 in columns where the digits (ones place) are aligned: $\begin{array}{c} 48 \\ -~7 \\ \end{array}$ Step 2: Subtract the units (8 - 7 = 1) and write the result in the units position.
Step 3: The tens place after subtraction is unchanged because there is no borrowing needed, so the 4 from 48 stays as 4.
Thus, we have: $\begin{array}{c} 48 \\ -~7 ~~\\ \underline{41} \end{array}$

Therefore, the solution to the problem is 41.

To solve this problem, let's use a methodical approach as follows:

• Step 1: Write the numbers in a vertical format, aligning the digits by place value.
• Step 2: Subtract the ones digit: $6$ (from $56$) minus $5$ equals $1$.
• Step 3: Bring down the tens digit since we are not subtracting anything from it: $5$.

In detail:

1. Align the numbers vertically, with the larger number on top:
   $\begin{array}{r} 56 \\ - \phantom{400}5 \\ \hline \end{array}$
2. Subtract the digits in the ones column. The ones digit in $56$ is $6$ and the ones digit in $5$ is $5$. Subtract $5$ from $6$ to get $1$.
3. Since there are no numbers to subtract from the tens column of the first number, write down the $5$ from $56$.

The result of the vertical subtraction is thus:
$\begin{array}{r} 56 \\ - \phantom{400}5 \\ \hline 51 \\ \end{array}$

Therefore, the solution to this problem is $51$.