32×75=
\( \frac{2}{3}\times\frac{5}{7}= \)
\( \frac{1}{4}\times\frac{4}{5}= \)
\( \frac{1}{4}\times\frac{3}{2}= \)
\( \frac{2}{3}\times\frac{1}{4}= \)
\( \frac{1}{6}\times\frac{2}{3}= \)
Let us solve the problem of multiplying the two fractions and .
Therefore, the solution to the problem is .
To multiply fractions, we multiply numerator by numerator and denominator by denominator
1*4 = 4
4*5 = 20
4/20
Note that we can simplify this fraction by 4
4/20 = 1/5
To solve the problem of multiplying the fractions and , we will follow these steps:
Now, let's work through each step:
Step 1: Multiply the numerators:
The numerators are and . Thus, .
Step 2: Multiply the denominators:
The denominators are and . Thus, .
Step 3: Write the result as a fraction and simplify:
The resulting fraction is . This fraction is already in simplest form.
Therefore, the solution to the problem is .
Among the choices provided, the correct answer is choice 3: .
To solve the problem of multiplying the fractions and , we will follow these steps:
Let's begin solving the problem:
Step 1: Multiply the numerators:
.
Step 2: Multiply the denominators:
.
Putting these together, the product of the fractions is:
.
Step 3: Simplify the fraction . Both the numerator and the denominator are divisible by 2:
Divide the numerator and denominator by 2:
.
Therefore, the product of and simplifies to .
From the given choices, the correct answer is choice 3: .
To solve the problem, we will calculate the product of the fractions and using the standard method for multiplying fractions.
Step 1: Multiply the numerators.
The numerators are 1 and 2. Thus, the product of the numerators is .
Step 2: Multiply the denominators.
The denominators are 6 and 3. Thus, the product of the denominators is .
Step 3: Form the resulting fraction from the products obtained in the previous steps.
This gives us the fraction .
Step 4: Simplify the fraction.
To simplify , find the greatest common divisor (GCD) of 2 and 18, which is 2. Divide both the numerator and the denominator by their GCD:
Therefore, the simplified result of is .
We compare this result with the multiple-choice options and confirm that the correct answer is:
\( \frac{2}{5}\times\frac{1}{2}= \)
\( \frac{3}{4}\times\frac{1}{2}= \)
\( \frac{3}{5}\times\frac{1}{2}= \)
\( \frac{7}{8}\times\frac{4}{6}= \)
\( \frac{2}{7}\times\frac{3}{5}= \)
To solve this problem, let's multiply the fractions and .
Step 1: Multiply the numerators:
Step 2: Multiply the denominators:
Step 3: Construct the fraction using the products from steps 1 and 2:
Step 4: Simplify the fraction. We can divide both the numerator and the denominator by their greatest common divisor, which is 2:
Thus, the product of and is .
Therefore, the solution to the problem is .
To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: The fractions are given as and . Multiplying the numerators, we get:
Step 2: Next, multiply the denominators:
Step 3: Combine these results to write the product of the fractions:
The resulting fraction is already in its simplest form, so no further simplification is necessary.
Therefore, the solution to the problem is .
To solve this problem, we need to multiply the fractions and .
Therefore, the solution to is .
The multiplication of fractions and requires the direct operation of multiplying numerators with numerators and denominators with denominators.
Now, we need to simplify . Find the greatest common divisor (GCD) of 28 and 48, which is 4.
Therefore, the solution to the problem is .
Thus, the correct answer is , which corresponds to choice 3.
To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: Multiply the numerators: .
Step 2: Multiply the denominators: .
Thus, the product of the fractions is .
Therefore, the solution to the problem is .
\( \frac{1}{3}\times\frac{4}{7}= \)
To solve this problem, we need to multiply two fractions, and , by following these steps:
This fraction, , is in its simplest form since there are no common factors between 4 and 21 other than 1.
Therefore, the solution to the problem is .