In this article, we will learn how to perform mathematical calculations with fractions.
More reading material:
- Addition of fractions
- Subtraction of fractions
- Multiplication of fractions
- Division of fractions
- Comparison of fractions
In this article, we will learn how to perform mathematical calculations with fractions.
More reading material:
Solve the following exercise:
\( \frac{1}{5}+\frac{1}{3}=\text{?} \)
Solve the following exercise:
\( \frac{1}{3}+\frac{2}{4}=\text{?} \)
Solve the following exercise:
\( \frac{1}{2}+\frac{2}{5}=\text{?} \)
Solve the following exercise:
\( \frac{3}{5}+\frac{1}{4}=\text{?} \)
Solve the following exercise:
\( \frac{1}{2}+\frac{2}{7}=\text{?} \)
Solve the following exercise:
To solve the problem of adding the fractions and , we follow these steps:
Therefore, when you add and , the solution is .
Solve the following exercise:
To solve this problem, let's follow these steps:
Step 1: Simplify . It simplifies to .
Step 2: The denominators are now 3 and 2. Find the least common multiple of 3 and 2, which is 6.
Step 3: Convert each fraction to have the common denominator of 6:
Step 4: Add the fractions:
Step 5: The fraction is already in its simplest form.
Therefore, the solution to the problem is .
Solve the following exercise:
To solve the problem of adding the fractions and , we will follow these steps:
Now, let’s explore each step in detail:
Step 1: The denominators are 2 and 5. A common denominator can be found by multiplying these two numbers: . Therefore, 10 is our common denominator.
Step 2: Convert each fraction to have the common denominator of 10.
- For , multiply both the numerator and the denominator by 5:
.
- For , multiply both the numerator and the denominator by 2:
.
Step 3: Add the fractions and :
Combine the numerators while keeping the common denominator:
.
Thus, .
Therefore, the sum of and is .
Solve the following exercise:
To solve the addition of fractions , follow these steps:
Thus, the sum of and is .
Solve the following exercise:
To solve the given problem of adding two fractions and , follow these steps:
The denominators of the fractions are and . Multiply these two numbers to find the common denominator: .
Convert to an equivalent fraction with a denominator of :
Convert to an equivalent fraction with a denominator of :
Now that both fractions have a common denominator, add them:
We have successfully added the fractions and obtained the result.
Therefore, the solution to the problem is .
Solve the following exercise:
\( \frac{1}{4}+\frac{3}{6}=\text{?} \)
Solve the following exercise:
\( \frac{1}{2}+\frac{1}{9}=\text{?} \)
Solve the following exercise:
\( \frac{2}{8}+\frac{1}{3}=\text{?} \)
Solve the following exercise:
\( \frac{1}{5}+\frac{2}{3}=\text{?} \)
Solve the following exercise:
\( \frac{1}{10}+\frac{1}{3}=\text{?} \)
Solve the following exercise:
To solve the problem of adding and , we need to find their sum using a common denominator.
Step 1: Identify the Least Common Denominator (LCD)
The denominators of the fractions are 4 and 6. The LCM of 4 and 6, which will be the least common denominator, is 12.
Step 2: Convert each fraction to an equivalent fraction with the denominator of 12.
For : Multiply the numerator and denominator by 3 to get .
For : Multiply the numerator and denominator by 2 to get .
Step 3: Add the fractions .
Step 4: Simplify the resulting fraction if necessary.
In this case, can be simplified. The greatest common divisor of 9 and 12 is 3, so .
Therefore, the sum of is , but in the context of the provided answer choices, we are looking for initially, which does match the simplified result before reducing.
The correct answer is therefore , which corresponds to Choice 3.
Solve the following exercise:
To solve this problem, we will add the fractions and by finding a common denominator.
Thus, the sum of the fractions and is .
Solve the following exercise:
To solve the problem of adding and , we need to first convert these fractions to have a common denominator.
Step 1: Find the least common denominator (LCD).
- The denominators of the fractions are and .
- The common denominator can be found by multiplying and , which gives us .
Step 2: Convert each fraction to an equivalent fraction with the common denominator of .
- For , multiply both the numerator and the denominator by :
.
- For , multiply both the numerator and the denominator by :
.
Step 3: Add the resulting fractions.
- .
Therefore, the solution to the problem is , which simplifies our answer.
Solve the following exercise:
To solve the problem of adding two fractions, follow these steps:
Therefore, the sum of is .
Solve the following exercise:
To solve the addition of fractions , we must first find a common denominator.
Step 1: Find the Least Common Multiple (LCM) of the denominators, 10 and 3. By multiplying these denominators, the LCM is .
Step 2: Rewrite each fraction with the common denominator of 30:
- Convert to an equivalent fraction with a denominator of 30. Multiply both numerator and denominator by 3:
- Convert to an equivalent fraction with a denominator of 30. Multiply both numerator and denominator by 10:
Step 3: Add the equivalent fractions:
Step 4: Simplify the resulting fraction. Since 13 is a prime number and does not divide 30, is already in its simplest form.
Thus, the sum of and is .
The correct answer is , which corresponds to choice 4.
Solve the following exercise:
\( \frac{1}{4}+\frac{2}{6}=\text{?} \)
Solve the following exercise:
\( \frac{2}{4}+\frac{2}{6}=\text{?} \)
Solve the following exercise:
\( \frac{1}{4}+\frac{4}{6}=\text{?} \)
Solve the following exercise:
\( \frac{3}{4}+\frac{1}{6}=\text{?} \)
Solve the following exercise:
\( \frac{2}{4}+\frac{1}{6}=\text{?} \)
Solve the following exercise:
To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: The denominators are 4 and 6. The least common multiple of 4 and 6 is 12.
Step 2: Convert each fraction to have the denominator 12.
For , multiplying the numerator and denominator by 3 gives .
For , multiplying the numerator and denominator by 2 gives .
Step 3: Add the fractions: .
Step 4: Check if can be simplified. Since 7 and 12 have no common factors other than 1, it is already in its simplest form.
Therefore, the sum of is .
Solve the following exercise:
To solve the fraction addition problem , follow these steps:
Step 1: Identify the least common denominator (LCD) of the fractions. The denominators are 4 and 6. The factors of 4 are 2 and 2, and the factors of 6 are 2 and 3. The LCD is the smallest number that both denominators divide into, which is 12.
Step 2: Convert each fraction to an equivalent fraction with the denominator of 12.
Step 3: For :
Find the equivalent fraction: Multiply both the numerator and denominator by 3 (since 4 * 3 = 12).
The equivalent fraction is .
Step 4: For :
Find the equivalent fraction: Multiply both the numerator and denominator by 2 (since 6 * 2 = 12).
The equivalent fraction is .
Step 5: Add the new fractions: .
Therefore, the sum of the fractions is .
Solve the following exercise:
To solve the problem of adding , follow these steps:
Therefore, the solution to the problem is .
Solve the following exercise:
To solve the addition of these two fractions, we'll proceed as follows:
Therefore, the solution to the problem is .
Solve the following exercise:
To solve the problem of adding and , follow these steps:
Step 1: Identify the least common denominator of the fractions.
The denominators of the fractions are 4 and 6. The least common multiple of 4 and 6 is 12, so 12 is our common denominator.
Step 2: Convert each fraction to an equivalent fraction with the denominator of 12.
For : Multiply both numerator and denominator by 3 to obtain . This is because .
For : Multiply both numerator and denominator by 2 to obtain . This is because .
Step 3: Add the converted fractions.
Step 4: Simplify the final fraction if possible.
In this case, can be simplified by dividing numerator and denominator by their greatest common divisor, which is 4. Thus, simplifies to .
However, as per the problem's required answer, the unsimplified fraction is .
Therefore, the solution to the problem is: