All Operations in Fractions: In combination with other operations

To solve the problem $\frac{2}{5} + \frac{1}{2} - \frac{1}{3}$, we will follow these steps:

• Step 1: Find the least common denominator (LCD) for $\frac{2}{5}$, $\frac{1}{2}$, and $\frac{1}{3}$.
• Step 2: Convert each fraction to have this common denominator.
• Step 3: Perform the arithmetic operations.
• Step 4: Simplify the result if necessary.

Now, let's proceed with the solution:
Step 1: The denominators are 5, 2, and 3. The least common multiple of these numbers is 30. Thus, the LCD is 30.

Step 2: Convert each fraction to have the common denominator of 30:
- Convert $\frac{2}{5}$ to a fraction with denominator 30: $\frac{2}{5} = \frac{2 \times 6}{5 \times 6} = \frac{12}{30}$.
- Convert $\frac{1}{2}$ to a fraction with denominator 30: $\frac{1}{2} = \frac{1 \times 15}{2 \times 15} = \frac{15}{30}$.
- Convert $\frac{1}{3}$ to a fraction with denominator 30: $\frac{1}{3} = \frac{1 \times 10}{3 \times 10} = \frac{10}{30}$.

Step 3: With all fractions having the same denominator, perform the operations:
$\frac{12}{30} + \frac{15}{30} - \frac{10}{30} = \frac{12 + 15 - 10}{30} = \frac{17}{30}$.

Step 4: Since $\frac{17}{30}$ is in its simplest form, no further simplification is needed.

Therefore, the correct answer is $\frac{17}{30}$.

To solve the expression $\frac{6}{7} - \frac{1}{2} + \frac{3}{14}$, we will follow these steps:

• Step 1: Find a common denominator for the fractions.
• Step 2: Convert each fraction to the common denominator.
• Step 3: Perform the subtraction and addition as required.
• Step 4: Simplify the result, if possible.

Let's work through the steps:

Step 1: The denominators are 7, 2, and 14. The least common multiple (LCM) of these numbers is 14.

Step 2: Convert each fraction:

• $\frac{6}{7}$ becomes $\frac{6 \times 2}{7 \times 2} = \frac{12}{14}$.
• $\frac{1}{2}$ becomes $\frac{1 \times 7}{2 \times 7} = \frac{7}{14}$.
• $\frac{3}{14}$ is already in the correct form as $\frac{3}{14}$.

Step 3: Perform the operations:

• Subtract: $\frac{12}{14} - \frac{7}{14} = \frac{5}{14}$.
• Add: $\frac{5}{14} + \frac{3}{14} = \frac{8}{14}$.

Step 4: Simplify the fraction if possible. Here, $\frac{8}{14}$ simplifies to $\frac{4}{7}$; however, since the given choices list $\frac{8}{14}$ and it matches, there is no need for further simplification within the context of this question.

Therefore, the solution to the problem is $\frac{8}{14}$.

To solve the expression $\frac{9}{10} - \frac{4}{5} + \frac{1}{2}$, we first seek a common denominator for the fractions. The denominators are 10, 5, and 2.

The least common multiple of these numbers is 10, as it is the smallest number that all denominators divide perfectly.

• Convert $\frac{4}{5}$ to a fraction with a denominator of 10: $\frac{4}{5} = \frac{4 \times 2}{5 \times 2} = \frac{8}{10}$.
• Convert $\frac{1}{2}$ to a fraction with a denominator of 10: $\frac{1}{2} = \frac{1 \times 5}{2 \times 5} = \frac{5}{10}$.

Now, the expression becomes $\frac{9}{10} - \frac{8}{10} + \frac{5}{10}$.

Perform the operations:

• Subtract: $\frac{9}{10} - \frac{8}{10} = \frac{1}{10}$.
• Add: $\frac{1}{10} + \frac{5}{10} = \frac{6}{10}$.

Thus, the value of the expression is $\frac{6}{10}$.

The correct answer is $\frac{6}{10}$.

To solve the expression $\frac{2}{7}+\frac{1}{2}-\frac{7}{14}$, follow these steps:

• Step 1: Find the least common multiple (LCM) of the denominators 7, 2, and 14. The LCM is 14.
• Step 2: Convert each fraction to have the denominator of 14:
  $\frac{2}{7}$ becomes $\frac{2 \times 2}{7 \times 2} = \frac{4}{14}$
  $\frac{1}{2}$ becomes $\frac{1 \times 7}{2 \times 7} = \frac{7}{14}$
  $\frac{7}{14}$ remains $\frac{7}{14}$ since it's already over 14.
• Step 3: Perform the operations in the expression $\frac{4}{14} + \frac{7}{14} - \frac{7}{14}$:
  First, add $\frac{4}{14} + \frac{7}{14} = \frac{11}{14}$.
  Then, subtract $\frac{11}{14} - \frac{7}{14} = \frac{4}{14}$.
• Step 4: The result is already simplified. Thus, the solution to the problem is $\frac{4}{14}$.

Therefore, the solution to the problem is $\mathbf{\frac{4}{14}}$, which corresponds to choice $\mathbf{3}$.

To solve the expression $\frac{4}{10} + \frac{1}{5} - \frac{1}{2}$, we will follow these steps:

• Step 1: Find a Common Denominator
  The denominators we have are 10, 5, and 2. The least common denominator (LCD) among these numbers is 10.

• Step 2: Convert Fractions to Equivalent Fractions with the LCD
  - $\frac{4}{10}$ is already using 10 as the denominator.
  - $\frac{1}{5} = \frac{1 \times 2}{5 \times 2} = \frac{2}{10}$.
  - $\frac{1}{2} = \frac{1 \times 5}{2 \times 5} = \frac{5}{10}$.

• Step 3: Perform the Arithmetic Operations
  Substitute the converted fractions into the original expression:
  $\frac{4}{10} + \frac{2}{10} - \frac{5}{10}$
  Combine the numerators over the common denominator:
  $\frac{4 + 2 - 5}{10} = \frac{1}{10}$

• Step 4: Simplify the Result
  The fraction $\frac{1}{10}$ is already in its simplest form.

Therefore, the solution to the problem is $\frac{1}{10}$.

To solve the problem, let's work through the following steps:

• Step 1: Identify the least common denominator (LCD) for all fractions.
  - The denominators are 8, 2, and 4. The LCM of these numbers is 8.

• Step 2: Convert each fraction to have this common denominator of 8.
  - $\frac{3}{8}$ is already with a denominator of 8.
  - $\frac{1}{2}$ can be rewritten as $\frac{4}{8}$ because $\frac{1 \times 4}{2 \times 4} = \frac{4}{8}$.
  - $\frac{1}{4}$ can be rewritten as $\frac{2}{8}$ because $\frac{1 \times 2}{4 \times 2} = \frac{2}{8}$.

• Step 3: Perform the arithmetic operations.
  - Add $\frac{3}{8}$ and $\frac{4}{8}$, which gives $\frac{3 + 4}{8} = \frac{7}{8}$.
  - Subtract $\frac{2}{8}$ from $\frac{7}{8}$, giving $\frac{7 - 2}{8} = \frac{5}{8}$.

• Step 4: Simplify the answer if necessary.
  $\frac{5}{8}$ is already in its simplest form.

Therefore, the solution to the problem is $\frac{5}{8}$.

To solve this problem, we'll follow these steps:

• Step 1: Multiply the given fractions.
• Step 2: Simplify if necessary.
• Step 3: Perform the addition of resulting fractions.

Now, let's work through each step:

Step 1: Multiply the fractions:
$\frac{1}{4} \times \frac{1}{2} = \frac{1 \times 1}{4 \times 2} = \frac{1}{8}$

Step 2: We find that the result is already simplified.

Step 3: Add $\frac{1}{8}$ to $\frac{3}{8}$:
$\frac{1}{8} + \frac{3}{8} = \frac{1 + 3}{8} = \frac{4}{8} = \frac{1}{2}$

The fractions have the same denominator, allowing for direct addition.

Therefore, the solution to the problem is $\frac{1}{2}$.

To solve this problem, we'll approach it in the following steps:

Step 1: Perform the Multiplication
The expression begins with multiplying two fractions: $\frac{1}{4} \times \frac{4}{5}$. Using the formula for multiplying fractions, we get:
$\frac{1 \times 4}{4 \times 5} = \frac{4}{20}$
Simplifying $\frac{4}{20}$ by dividing both numerator and denominator by 4 gives:
$\frac{1}{5}$

Step 2: Add the Result to the Second Fraction
Now, we need to add $\frac{1}{5}$ to $\frac{11}{20}$. To do this, we first find a common denominator.
The least common denominator between 5 and 20 is 20. Convert $\frac{1}{5}$ to twentieths:
$\frac{1}{5} = \frac{4}{20}$
Now add $\frac{4}{20}$ to $\frac{11}{20}$:
$\frac{4}{20} + \frac{11}{20} = \frac{15}{20}$

Step 3: Simplify the Final Result
Simplify $\frac{15}{20}$ by dividing the numerator and the denominator by 5:
$\frac{15 \div 5}{20 \div 5} = \frac{3}{4}$

Therefore, the solution to the problem is $\frac{3}{4}$. This matches choice 1, which is $\frac{3}{4}$.

To solve this mathematical problem, follow these steps:

• Step 1: Multiply the fractions $\frac{3}{4}$ and $\frac{3}{4}$.
• Step 2: Subtract $\frac{1}{4}$ from the product obtained in Step 1.

Let's execute each step in detail:

Step 1: Calculate the product of $\frac{3}{4}$ and $\frac{3}{4}$.

To multiply two fractions, multiply their numerators and their denominators separately:

$\frac{3}{4} \times \frac{3}{4} = \frac{3 \times 3}{4 \times 4} = \frac{9}{16}$

Step 2: Subtract $\frac{1}{4}$ from $\frac{9}{16}$.

Before we subtract $\frac{1}{4}$ from $\frac{9}{16}$, we need a common denominator. The common denominator for these fractions is 16:

$\frac{1}{4} = \frac{1 \times 4}{4 \times 4} = \frac{4}{16}$

Now subtract $\frac{4}{16}$ from $\frac{9}{16}$:

$\frac{9}{16} - \frac{4}{16} = \frac{9 - 4}{16} = \frac{5}{16}$

Therefore, the solution to the given problem is $\frac{5}{16}$.

To solve $\frac{1}{2} \times \frac{1}{2} + \frac{3}{4}$, follow these steps:

• Step 1: Multiply $\frac{1}{2} \times \frac{1}{2}$ by using the multiplication of fractions formula:
  $\frac{1}{2} \times \frac{1}{2} = \frac{1 \times 1}{2 \times 2} = \frac{1}{4}$.
• Step 2: Add $\frac{1}{4}$ to $\frac{3}{4}$.
  Since $\frac{1}{4}$ and $\frac{3}{4}$ already have the same denominator, the addition can be done directly:
  $\frac{1}{4} + \frac{3}{4} = \frac{1 + 3}{4} = \frac{4}{4} = 1$.

Therefore, the correct solution to the expression is $1$.

To solve this problem, we'll follow these steps:

• Step 1: Multiply the first two fractions.
• Step 2: Add the result to the third fraction.
• Step 3: Simplify the final result.

Now, let's work through each step:
Step 1: Multiply $\frac{4}{5}$ by $\frac{1}{2}$. According to the multiplication rule for fractions, we have:
$\frac{4}{5} \times \frac{1}{2} = \frac{4 \times 1}{5 \times 2} = \frac{4}{10}$ Step 2: We need to add $\frac{4}{10}$ to $\frac{3}{10}$. Since these fractions have the same denominator, we can add them directly:
$\frac{4}{10} + \frac{3}{10} = \frac{4 + 3}{10} = \frac{7}{10}$ Step 3: The sum $\frac{7}{10}$ is already in simplest form.

Therefore, the solution to the problem is $\frac{7}{10}$, which matches choice $\text{(3)}$.

To solve the problem $\frac{3}{5} \times \frac{2}{3} + \frac{2}{5}$, we proceed with the following steps:

• Step 1: Multiply the fractions $\frac{3}{5}$ and $\frac{2}{3}$.

The multiplication yields:

$\frac{3}{5} \times \frac{2}{3} = \frac{3 \times 2}{5 \times 3} = \frac{6}{15}$

• Step 2: Simplify the product $\frac{6}{15}$.

Both 6 and 15 share a common factor of 3:

$\frac{6}{15} = \frac{6 \div 3}{15 \div 3} = \frac{2}{5}$

• Step 3: Add $\frac{2}{5}$ to the simplified result $\frac{2}{5}$.

Since the fractions $\frac{2}{5}$ and $\frac{2}{5}$ have the same denominator, add the numerators while keeping the denominator:

$\frac{2}{5} + \frac{2}{5} = \frac{2+2}{5} = \frac{4}{5}$

Therefore, the solution to the problem is $\frac{4}{5}$.

To solve this problem, let's follow these steps:

• Step 1: Multiply the fractions. Calculate $\frac{2}{3} \times \frac{1}{3}$.
• Step 2: Add the product to another fraction. Add the result to $\frac{2}{9}$.

Now, let's work through the calculations:

Step 1: Multiply $\frac{2}{3}$ by $\frac{1}{3}$.

The formula for multiplying fractions is:

$\frac{a}{b} \times \frac{c}{d} = \frac{a \times c}{b \times d}$.

Substitute the values:

$\frac{2}{3} \times \frac{1}{3} = \frac{2 \times 1}{3 \times 3} = \frac{2}{9}$.

Step 2: Add $\frac{2}{9}$ to the product.

We found in Step 1 that $\frac{2}{3} \times \frac{1}{3} = \frac{2}{9}$.

Now add $\frac{2}{9} + \frac{2}{9} = \frac{2 + 2}{9} = \frac{4}{9}$.

Therefore, the solution to the expression is $\frac{4}{9}$.

To solve the problem $\frac{3}{4} \times \frac{1}{2} + \frac{5}{8}$, we'll follow these steps:

• Step 1: Multiply the fractions $\frac{3}{4} \times \frac{1}{2}$.
• Step 2: Add the result to $\frac{5}{8}$.

Now, let's work through the steps:

Step 1: Compute the product of the first two fractions:
$\frac{3}{4} \times \frac{1}{2} = \frac{3 \times 1}{4 \times 2} = \frac{3}{8}$

Step 2: Add the resulting fraction to $\frac{5}{8}$ by finding a common denominator:

The fractions $\frac{3}{8}$ and $\frac{5}{8}$ already have the same denominator, so we can simply add them:
$\frac{3}{8} + \frac{5}{8} = \frac{3 + 5}{8} = \frac{8}{8} = 1$

Therefore, the solution to the problem is $1$.

To solve the expression $\frac{4}{4} \times \frac{1}{2} + \frac{3}{8}$, follow these steps:

• Step 1: Simplify $\frac{4}{4}$. Since $\frac{4}{4} = 1$, the expression becomes $1 \times \frac{1}{2} + \frac{3}{8}$.
• Step 2: Perform the multiplication.
  Calculate $1 \times \frac{1}{2} = \frac{1}{2}$.
• Step 3: Add $\frac{1}{2}$ to $\frac{3}{8}$.
  First, convert $\frac{1}{2}$ to an equivalent fraction with a denominator of 8: $\frac{1}{2} = \frac{4}{8}$.
• Step 4: Now, add the fractions: $\frac{4}{8} + \frac{3}{8} = \frac{7}{8}$.

Thus, the final result is $\frac{7}{8}$.

To solve the given problem, we will follow these steps:

• Step 1: Perform the multiplication of the fractions.
• Step 2: Simplify the result, if applicable.
• Step 3: Add the simplified fractional result to the given fraction, ensuring the denominators align properly.
• Step 4: Simplify the final result, if necessary.

Let's go through each step:

Step 1: Multiply the fractions $\frac{2}{3} \times \frac{2}{3} = \frac{2 \times 2}{3 \times 3} = \frac{4}{9}$.

Step 2: The result from step 1 is $\frac{4}{9}$, which cannot be further simplified.

Step 3: Add the result from Step 2 to $\frac{4}{9}$ given in the problem:
We have two fractions $\frac{4}{9}$ and $\frac{4}{9}$, and since they already have a common denominator, we add them directly:
$\frac{4}{9} + \frac{4}{9} = \frac{4 + 4}{9} = \frac{8}{9}$.

Step 4: The fraction $\frac{8}{9}$ is already in its simplest form.

Therefore, the solution to the problem is $\frac{8}{9}$.

To solve this problem, we'll perform the following steps:

• Step 1: Determine a common denominator for the fractions.
• Step 2: Convert each fraction to have this common denominator.
• Step 3: Perform the addition and subtraction operations on these fractions.
• Step 4: Simplify the resulting fraction, if possible.

Now, let's work through each step:

Step 1: To combine $\frac{3}{5}$, $\frac{1}{5}$, and $\frac{3}{15}$, identify the least common denominator (LCD). The denominators here are 5, 5, and 15. The least common multiple of 5 and 15 is 15. Therefore, our common denominator is 15.

Step 2: Convert each fraction to an equivalent fraction with a denominator of 15:
$\frac{3}{5} = \frac{3 \times 3}{5 \times 3} = \frac{9}{15}$,
$\frac{1}{5} = \frac{1 \times 3}{5 \times 3} = \frac{3}{15}$,
$\frac{3}{15}$ is already with the common denominator.

Step 3: Add and subtract the fractions:
$\frac{9}{15} + \frac{3}{15} = \frac{12}{15}$
$\frac{12}{15} - \frac{3}{15} = \frac{9}{15}$.

Step 4: Simplify the resulting fraction:
$\frac{9}{15} = \frac{3}{5}$ (dividing the numerator and denominator by their greatest common divisor, which is 3).

Therefore, the solution to the problem is $\frac{3}{5}$.

To solve this problem, we will follow these steps:

• Step 1: Find the least common denominator (LCD) for the fractions.
• Step 2: Convert each fraction to an equivalent fraction with the common denominator.
• Step 3: Perform the operations in the given order, subtraction first, then addition.

Now, let's work through each step:

Step 1: The denominators of the given fractions are 5 and 15. The least common multiple (LCM) of these numbers is 15, so 15 will be our common denominator.

Step 2: Convert each fraction to have the denominator of 15:
- $\frac{3}{5}$ is converted by multiplying both the numerator and denominator by 3, resulting in $\frac{9}{15}$.
- $\frac{1}{5}$ is converted by multiplying both the numerator and denominator by 3, yielding $\frac{3}{15}$.
- $\frac{3}{15}$ is already in terms of the common denominator.

Step 3: Perform the subtraction and addition:
- Start by subtracting $\frac{3}{15}$ from $\frac{9}{15}$:

$\frac{9}{15} - \frac{3}{15} = \frac{6}{15}$

Now, add $\frac{6}{15}$ and $\frac{3}{15}$:

$\frac{6}{15} + \frac{3}{15} = \frac{9}{15}$

Finally, simplify $\frac{9}{15}$ by dividing the numerator and denominator by their greatest common divisor, which is 3:

$\frac{9}{15} = \frac{3}{5}$

Therefore, the solution to the problem is $\frac{3}{5}$.

To solve this problem, we'll follow these steps:

• Simplify each fraction.

• Identify the least common denominator (LCD).

• Convert each fraction to have this common denominator.

• Perform the addition and subtraction.

• Simplify the final result.

Let's work through each step:
Step 1: Simplify each fraction.
- $\frac{3}{6}$ simplifies to $\frac{1}{2}$ because both the numerator and denominator are divisible by 3.
- $\frac{2}{4}$ simplifies to $\frac{1}{2}$ because both the numerator and denominator are divisible by 2.
- $\frac{1}{12}$ is already in its simplest form.

Step 2: Identify the least common denominator (LCD).
- The denominators now are 2, 2, and 12. The LCD of 2 and 12 is 12.

Step 3: Convert each fraction to have this common denominator.
- $\frac{1}{2} = \frac{6}{12}$ (since $1 \times 6 = 6$ and $2 \times 6 = 12$)
- $\frac{1}{2} = \frac{6}{12}$ (similarly converted)
- $\frac{1}{12} = \frac{1}{12}$ (already has the denominator 12)

Step 4: Perform the addition and subtraction:
$\frac{6}{12} - \frac{6}{12} + \frac{1}{12} = \frac{6 - 6 + 1}{12} = \frac{1}{12}$

Step 5: Simplify the final result:
The result $\frac{1}{12}$ is already in its simplest form.

Therefore, the solution to the problem is $\frac{1}{12}$.

To solve the problem, follow these steps:

• Step 1: Convert each fraction to have a common denominator.
• Step 2: Add and subtract the fractions.
• Step 3: Simplify the result.

Let's work through these steps:

Step 1: Find the Least Common Denominator (LCD) of the fractions involved. The denominators are 6, 4, and 12. The LCM of these numbers is 12, so the LCD is 12.

Convert each fraction to this common denominator:

• $\frac{3}{6}$ becomes $\frac{3 \times 2}{6 \times 2} = \frac{6}{12}$
• $\frac{2}{4}$ becomes $\frac{2 \times 3}{4 \times 3} = \frac{6}{12}$
• $\frac{1}{12} \text{ remains } \frac{1}{12}$

Step 2: Perform the operations using these equivalent fractions: $\frac{6}{12} + \frac{6}{12} - \frac{1}{12} = \frac{6 + 6 - 1}{12} = \frac{11}{12}$

Step 3: Check if the result can be simplified further. In this case, $\frac{11}{12}$ is already in simplest form.

Therefore, the solution to the problem is $\frac{11}{12}$.