The kite ABCD shown below has an area of 42 cm².
AB = BC
DC = AD
BD = 14
The diagonals of the kite intersect at point 0.
Calculate the length of side AO.
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The kite ABCD shown below has an area of 42 cm².
AB = BC
DC = AD
BD = 14
The diagonals of the kite intersect at point 0.
Calculate the length of side AO.
We substitute the data we have into the formula for the area of the kite:
We multiply by 2 to remove the denominator:
Then divide by 14:
In a rhombus, the main diagonal crosses the second diagonal, therefore:
3 cm
Indicate the correct answer
The next quadrilateral is:
AC is the full diagonal from vertex A to vertex C, while AO is half the diagonal from vertex A to the center O. Since diagonals bisect each other in kites, AO = AC/2.
Kites have perpendicular diagonals that bisect each other, making the area formula perfect for these shapes. It's much easier than breaking into triangles!
It doesn't matter! The area formula works with any two perpendicular diagonals. In this problem, BD = 14 is given, and we need to find AC to use the formula.
Yes! You could split the kite into four right triangles and use their areas, but the diagonal method is much faster and less prone to errors.
Check your algebra! From , multiply both sides by 2 to get , then divide by 14: AC = 6.
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