Calculate Triangle and Trapezoid Measurements: Finding Lengths 6, 9, and 4.5

Question

666999AAABBBCCCDDDVVVFFF4.5643

Choose the correct answer.

Video Solution

Solution Steps

00:00 Choose the correct answer
00:03 We want to find the ratio of sides
00:06 Let's substitute the side values according to the given data
00:11 We'll break down each number into factors with (3) and reduce
00:15 This is the ratio of sides
00:18 Let's find another side ratio
00:27 We can see that here too the similarity ratio is equal
00:36 And for this pair of sides too, we can see the ratio is equal
00:53 All ratios are equal, therefore the triangles are similar
00:58 And this is the solution to the question

Step-by-Step Solution

This problem involves identifying the correct similarity ratio of triangles based on given line segments. We have triangle ACF \triangle ACF with line segments AC AC and CF CF , and triangle BDV \triangle BDV with line segments BD BD and DV DV , where corresponding side lengths of similar triangles should satisfy proportional relationships.

First, recognize that for similar triangles, the ratio of corresponding sides should be equal. If triangles ACF \triangle ACF and BDV \triangle BDV are similar, the segments would meet certain proportional criteria. The possible ratios could be formed by recognizing:

  • FVAC \frac{FV}{AC} should correspond to the smaller segment extending from a vertex to base or equivalent in the other triangle setup.
  • DVAB \frac{DV}{AB} matches up the vertex downward extension similar to FVAC \frac{FV}{AC} with a base side.
  • FDBC \frac{FD}{BC} must be the ratio of a cross-cutting or diagonal side ratio to maintain similarity from base to opposite corner.

Thus, the correct setup for these segments should reflect that:
FVAC=DVAB=FDBC \frac{FV}{AC} = \frac{DV}{AB} = \frac{FD}{BC}

By evaluating each choice given, the correct answer would align with this reasoning. Therefore, the correct choice is: FVAC=DVAB=FDBC \frac{FV}{AC} = \frac{DV}{AB} = \frac{FD}{BC} .

Answer

FVAC=DVAB=FDBC \frac{FV}{AC}=\frac{DV}{AB}=\frac{FD}{BC}