Check the True Statement: Geometry Challenge with S = X² and P = 4X

Question

Given a square of side length X

We will mark the area of the square by S and the perimeter of the square by P

Check the correct statement

Video Solution

Solution Steps

00:00 Mark the correct statement
00:03 Use the formula to calculate square area (side squared)
00:08 Use the formula to calculate square perimeter (4 times side)
00:16 Sum of perimeter and area
00:21 Add 4
00:33 Break down 4 into factors 2 and 2
00:39 Use shortened multiplication formulas to find the brackets
00:44 And this is the solution to the question

Step-by-Step Solution

To solve this problem, we begin by calculating the area and the perimeter of the square:

  • Perimeter, P=4X P = 4X
  • Area, S=X2 S = X^2

The sum of P P and S S is:

P+S=4X+X2 P + S = 4X + X^2

We need to evaluate the choice that correctly equates:

Given the choice P+S+4=(X+2)2 P + S + 4 = (X + 2)^2 , we expand and simplify:

  • (X+2)2=X2+4X+4 (X + 2)^2 = X^2 + 4X + 4
  • This expression matches P+S+4=X2+4X+4 P + S + 4 = X^2 + 4X + 4 .

Thus, the expression P+S+4=(X+2)2 P + S + 4 = (X + 2)^2 is correct.

Therefore, the solution to the problem is P+S+4=(x+2)2 P+S+4=(x+2)^2 .

Answer

P+S+4=(x+2)2 P+S+4=(x+2)^2