Check the True Statement: Geometry Challenge with S = X² and P = 4X

Square Formulas with Algebraic Verification

Given a square of side length X

We will mark the area of the square by S and the perimeter of the square by P

Check the correct statement

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:09 Let's identify the correct statement.
00:12 Start by calculating the square's area. Use the side times itself.
00:17 Now, find the square's perimeter. Multiply the side length by four.
00:25 Next, add the perimeter and the area together.
00:30 Then, add four to your result.
00:42 Break down four into two times two.
00:48 Use quick multiplication tricks to find the terms in brackets.
00:53 And that's how you solve this problem!

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Given a square of side length X

We will mark the area of the square by S and the perimeter of the square by P

Check the correct statement

2

Step-by-step solution

To solve this problem, we begin by calculating the area and the perimeter of the square:

  • Perimeter, P=4X P = 4X
  • Area, S=X2 S = X^2

The sum of P P and S S is:

P+S=4X+X2 P + S = 4X + X^2

We need to evaluate the choice that correctly equates:

Given the choice P+S+4=(X+2)2 P + S + 4 = (X + 2)^2 , we expand and simplify:

  • (X+2)2=X2+4X+4 (X + 2)^2 = X^2 + 4X + 4
  • This expression matches P+S+4=X2+4X+4 P + S + 4 = X^2 + 4X + 4 .

Thus, the expression P+S+4=(X+2)2 P + S + 4 = (X + 2)^2 is correct.

Therefore, the solution to the problem is P+S+4=(x+2)2 P+S+4=(x+2)^2 .

3

Final Answer

P+S+4=(x+2)2 P+S+4=(x+2)^2

Key Points to Remember

Essential concepts to master this topic
  • Formulas: Square area S = X² and perimeter P = 4X
  • Technique: Expand (X + 2)² = X² + 4X + 4 to match expressions
  • Check: Substitute values to verify P + S + 4 equals the expanded form ✓

Common Mistakes

Avoid these frequent errors
  • Confusing area and perimeter formulas
    Don't mix up S = 4X and P = X² = wrong calculations! This switches the basic square formulas and leads to incorrect algebraic expressions. Always remember area uses the exponent (S = X²) while perimeter uses multiplication (P = 4X).

Practice Quiz

Test your knowledge with interactive questions

Choose the expression that has the same value as the following:


\( (x+3)^2 \)

FAQ

Everything you need to know about this question

Why do we add 4 to P + S in the correct answer?

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Adding 4 creates a perfect square trinomial! Since P+S=4X+X2 P + S = 4X + X^2 , adding 4 gives us X2+4X+4 X^2 + 4X + 4 , which factors perfectly as (X+2)2 (X + 2)^2 .

How do I remember the difference between area and perimeter?

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Area measures the space inside the square, so we multiply length × width = X². Perimeter measures the border around the square, so we add all four sides = 4X.

What happens if I expand (X + 4)² instead?

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Expanding (X+4)2 (X + 4)^2 gives X2+8X+16 X^2 + 8X + 16 . This doesn't match P+S+4=X2+4X+4 P + S + 4 = X^2 + 4X + 4 because the middle term is 8X instead of 4X.

Can I solve this by plugging in a specific value for X?

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Yes! Try X = 3: P = 12, S = 9, so P + S + 4 = 25. Check: (3+2)2=52=25 (3 + 2)^2 = 5^2 = 25 ✓. This confirms the correct answer!

Why is this called a perfect square trinomial?

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A perfect square trinomial has the pattern a2+2ab+b2=(a+b)2 a^2 + 2ab + b^2 = (a + b)^2 . Here, X2+4X+4 X^2 + 4X + 4 fits this pattern with a = X and b = 2.

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