Given that the length of the sides of square 1 is 6
and the length of the side of square 2 is 7.
Which square has the larger area, 1 or 2?
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Given that the length of the sides of square 1 is 6
and the length of the side of square 2 is 7.
Which square has the larger area, 1 or 2?
To solve this problem, we will calculate the area of each square and compare them:
Let's work through these steps:
Step 1:
The area of a square is calculated using the formula:
For square 1, the side length is 6:
Step 2:
For square 2, the side length is 7:
Step 3:
Now, compare the two areas:
(Area of square 1) is less than (Area of square 2).
Therefore, square 2 has a larger area.
Based on our calculations, the square with the larger area is square 2.
2
\( 11^2= \)
The question asks for area comparison, not side length! While 7 > 6 for sides, you must calculate the actual areas: and .
Side length is the distance along one edge (measured in units like cm). Area is the space inside the square (measured in square units like cm²). Area grows much faster than side length!
A square has equal length and width. To find area, you multiply length × width. Since both are the same value, you get side × side = side². That's why we square it!
Square 2 has area 49 and square 1 has area 36. The difference is 13 square units. You can also say square 2's area is about 1.36 times larger than square 1's area.
The question doesn't specify units, so just the numbers are fine. But remember that areas are measured in square units (like cm² or m²) in real-world problems.
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