Compare Square Areas: 6 vs 7 Side Length Analysis

Question

Given that the length of the sides of square 1 is 6

and the length of the side of square 2 is 7.

Which square has the larger area, 1 or 2?

Video Solution

Solution Steps

00:09 Which square has a larger area?
00:12 To find the area, we use the formula: side times side.
00:17 Now, we'll plug in the values and solve for the area.
00:20 Here, we have the area of square one.
00:23 Next, let's apply the same steps for square two.
00:29 Let's compare them to see which area is bigger.
00:34 And that's how we solve this problem!

Step-by-Step Solution

To solve this problem, we will calculate the area of each square and compare them:

  • Step 1: Calculate the area of square 1.
  • Step 2: Calculate the area of square 2.
  • Step 3: Compare the areas to find which square has a larger area.

Let's work through these steps:

Step 1:

The area of a square is calculated using the formula:

Area=side length2 \text{Area} = \text{side length}^2

For square 1, the side length is 6:

Area1=62=36 \text{Area}_1 = 6^2 = 36

Step 2:

For square 2, the side length is 7:

Area2=72=49 \text{Area}_2 = 7^2 = 49

Step 3:

Now, compare the two areas:

36 36 (Area of square 1) is less than 49 49 (Area of square 2).

Therefore, square 2 has a larger area.

Based on our calculations, the square with the larger area is square 2.

Answer

2