Determine Intersection Points for y = (x - 11)(x + 1)

X-intercepts with Factored Quadratic Functions

Determine the points of intersection of the function

y=(x11)(x+1) y=(x-11)(x+1)

With the X

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:09 Let's find where the graph crosses the X-axis.
00:13 At these points, the Y value is zero.
00:17 So, we set Y to zero and solve for X.
00:22 Look at each factor to see what makes them zero.
00:28 Here, we have one solution for X.
00:37 And here is another solution for X.
00:45 That's how we find the solution to the problem!

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Determine the points of intersection of the function

y=(x11)(x+1) y=(x-11)(x+1)

With the X

2

Step-by-step solution

To determine the points where the function intersects the x-axis, we need to find the x-intercepts. These occur where y=0 y = 0 .

The function is given as y=(x11)(x+1) y = (x-11)(x+1) . To find the x-intercepts, we set this function equal to zero:

(x11)(x+1)=0 (x-11)(x+1) = 0 .

This equation implies that the product is zero when either x11=0 x-11 = 0 or x+1=0 x+1 = 0 .

Solving these equations, we find:

  • x11=0 x-11 = 0 leads to x=11 x = 11 .
  • x+1=0 x+1 = 0 leads to x=1 x = -1 .

Thus, the points of intersection with the x-axis are (1,0)(-1, 0) and (11,0)(11, 0).

Therefore, the solution to the problem is (1,0),(11,0)(-1, 0), (11, 0).

3

Final Answer

(1,0),(11,0) (-1,0),(11,0)

Key Points to Remember

Essential concepts to master this topic
  • Zero Product Property: If (a)(b) = 0, then a = 0 or b = 0
  • Technique: Set each factor equal to zero: x - 11 = 0 and x + 1 = 0
  • Check: Substitute back: (-1 - 11)(-1 + 1) = (-12)(0) = 0 ✓

Common Mistakes

Avoid these frequent errors
  • Setting the entire expression equal to the x-value instead of zero
    Don't set (x - 11)(x + 1) = x to find intersections = wrong equation! This finds where the parabola equals the line y = x, not the x-axis. Always set the function equal to zero when finding x-intercepts.

Practice Quiz

Test your knowledge with interactive questions

The following function has been graphed below:

\( f(x)=-x^2+5x+6 \)

Calculate points A and B.

BBBAAACCC

FAQ

Everything you need to know about this question

Why do we set the function equal to zero?

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X-intercepts occur where the graph crosses the x-axis. On the x-axis, the y-coordinate is always zero, so we need y=0 y = 0 .

What if the function wasn't already factored?

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You'd need to factor the quadratic first! For example, x210x11=0 x^2 - 10x - 11 = 0 factors to (x11)(x+1)=0 (x - 11)(x + 1) = 0 , then solve the same way.

Can a quadratic have more than two x-intercepts?

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No! A quadratic function can have at most two x-intercepts. It could also have one (touching the x-axis) or none (not crossing the x-axis).

How do I remember which coordinates go where?

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Remember: x-intercepts have the form (x-value, 0). The y-coordinate is always zero because you're on the x-axis!

What's the difference between roots and x-intercepts?

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They're the same thing! Roots, zeros, x-intercepts, and solutions all refer to the x-values where y=0 y = 0 .

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