Determine the Intersection Points of y=(-2x+4)(x+3) with the X-Axis

Question

Determine the points of intersection of the function

y=(2x+4)(x+3) y=(-2x+4)(x+3)

With the X

Video Solution

Solution Steps

00:00 Find the intersection point with the X-axis
00:03 At the intersection point with the X-axis, the Y value must = 0
00:07 Substitute Y = 0 and solve for X values
00:13 Find what makes each factor zero in the multiplication
00:18 This is one solution
00:42 This is the second solution
00:48 And this is the solution to the question

Step-by-Step Solution

To solve the problem, we need to find the x-intercepts of the quadratic function:

y=(2x+4)(x+3) y = (-2x + 4)(x + 3)

The x-intercepts occur where the function equals zero, i.e., when y=0 y = 0 . Since the function is in factored form, we apply the zero-product property:

  • Set each factor equal to zero:
  • (2x+4)=0(-2x + 4) = 0
  • x+3=0x + 3 = 0

Next, solve each equation for x x :

  • For (2x+4)=0(-2x + 4) = 0:
    • Subtract 4 from both sides: 2x=4-2x = -4
    • Divide by -2: x=2x = 2
  • For x+3=0x + 3 = 0:
    • Subtract 3 from both sides: x=3x = -3

Therefore, the function intersects the x-axis at the points (3,0)(-3, 0) and (2,0)(2, 0).

Additionally, when correlating with answer choices, choice 2 matches our derived solution:

(3,0),(2,0)(-3, 0), (2, 0)

Answer

(3,0),(2,0) (-3,0),(2,0)