Determine the Intersection Points of y=(-2x+4)(x+3) with the X-Axis

Quadratic Functions with Factored Form

Determine the points of intersection of the function

y=(2x+4)(x+3) y=(-2x+4)(x+3)

With the X

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find the intersection point with the X-axis
00:03 At the intersection point with the X-axis, the Y value must = 0
00:07 Substitute Y = 0 and solve for X values
00:13 Find what makes each factor zero in the multiplication
00:18 This is one solution
00:42 This is the second solution
00:48 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Determine the points of intersection of the function

y=(2x+4)(x+3) y=(-2x+4)(x+3)

With the X

2

Step-by-step solution

To solve the problem, we need to find the x-intercepts of the quadratic function:

y=(2x+4)(x+3) y = (-2x + 4)(x + 3)

The x-intercepts occur where the function equals zero, i.e., when y=0 y = 0 . Since the function is in factored form, we apply the zero-product property:

  • Set each factor equal to zero:
  • (2x+4)=0(-2x + 4) = 0
  • x+3=0x + 3 = 0

Next, solve each equation for x x :

  • For (2x+4)=0(-2x + 4) = 0:
    • Subtract 4 from both sides: 2x=4-2x = -4
    • Divide by -2: x=2x = 2
  • For x+3=0x + 3 = 0:
    • Subtract 3 from both sides: x=3x = -3

Therefore, the function intersects the x-axis at the points (3,0)(-3, 0) and (2,0)(2, 0).

Additionally, when correlating with answer choices, choice 2 matches our derived solution:

(3,0),(2,0)(-3, 0), (2, 0)

3

Final Answer

(3,0),(2,0) (-3,0),(2,0)

Key Points to Remember

Essential concepts to master this topic
  • Zero Product Property: If AB = 0, then A = 0 or B = 0
  • Technique: Set each factor equal to zero: (-2x+4)=0 gives x=2
  • Check: Substitute back: y=(-2(2)+4)(2+3) = (0)(5) = 0 ✓

Common Mistakes

Avoid these frequent errors
  • Finding y-intercepts instead of x-intercepts
    Don't substitute x=0 to find where the graph crosses the x-axis = gives you y-intercept (0,12) instead! This confuses axes and gives coordinate pairs with wrong positions. Always set y=0 when finding x-intercepts.

Practice Quiz

Test your knowledge with interactive questions

The following function has been graphed below:

\( f(x)=-x^2+5x+6 \)

Calculate points A and B.

BBBAAACCC

FAQ

Everything you need to know about this question

Why do I set the whole function equal to zero?

+

X-intercepts occur where the graph crosses the x-axis, which means the y-coordinate is 0. So we set y=0 y = 0 to find these special x-values!

What if the function wasn't already factored?

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You'd need to factor the quadratic first or use the quadratic formula. The factored form y=(ax+b)(cx+d) y = (ax + b)(cx + d) makes finding x-intercepts much easier!

How do I know which coordinate goes first?

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Remember: (x, y) always! For x-intercepts, the y-coordinate is always 0, so you get points like (2,0) (2, 0) and (3,0) (-3, 0) .

Can a quadratic have more than 2 x-intercepts?

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No! A quadratic function can have at most 2 x-intercepts. It could also have 1 (if it just touches the x-axis) or 0 (if it doesn't cross the x-axis at all).

What does the zero product property actually mean?

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If two numbers multiply to give zero, then at least one of them must be zero. It's impossible for two non-zero numbers to multiply and get zero!

Do I need to expand the factored form first?

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No! Keep it factored! The factored form (2x+4)(x+3)=0 (-2x + 4)(x + 3) = 0 makes it much easier to apply the zero product property directly.

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