Find Intersection Points of the Quadratic: y=(-x-3)(x-1) with the X-axis

Question

Determine the points of intersection of the function

$y=(-x-3)(x-1)$

With the X

00:00 Find the intersection point with the X-axis

00:03 At the intersection point with the X-axis, the Y value must = 0

00:07 Substitute Y = 0 and solve for X values

00:13 Find what zeros each factor in the product

00:16 This is one solution

00:28 This is the second solution

00:32 And this is the solution to the question

To solve for the x-intercepts of the function $y = (-x-3)(x-1)$ , we need to find where $y = 0$ .

The equation becomes:

$(-x-3)(x-1) = 0$

This equation is satisfied if either of the factors equals zero:

Set the first factor to zero: $-x - 3 = 0$ .
Solve for $x$ : $-x = 3$ , therefore $x = -3$ .
Set the second factor to zero: $x - 1 = 0$ .
Solve for $x$ : $x = 1$ .

Thus, the x-intercepts are $(-3, 0)$ and $(1, 0)$ .

These correspond with option 3 from the list of choices.

Therefore, the points of intersection of the function with the x-axis are $(1,0),(-3,0)$ .

$(1,0),(-3,0)$