Finding Intersection Points: Solve for x in y = (x-1)(x+10)

X-Intercepts with Factored Quadratics

Determine the points of intersection of the function

y=(x1)(x+10) y=(x-1)(x+10)

With the X

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find the intersection point with the X-axis
00:03 At the intersection point with X-axis, Y value must = 0
00:07 Substitute Y = 0 and solve to find X values
00:13 Find what makes each factor zero in the multiplication
00:20 This is one solution
00:28 This is second solution
00:33 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Determine the points of intersection of the function

y=(x1)(x+10) y=(x-1)(x+10)

With the X

2

Step-by-step solution

To find where the function intersects the x-axis, we set y=(x1)(x+10)=0 y = (x - 1)(x + 10) = 0 .

Using the Zero Product Property, if the product equals zero, at least one of the factors must be zero:

  • If (x1)=0 (x - 1) = 0 , then x=1 x = 1 .
  • If (x+10)=0 (x + 10) = 0 , then x=10 x = -10 .

Thus, the function intersects the x-axis at the points where x=1 x = 1 and x=10 x = -10 . These give us the points (1,0)(1, 0) and (10,0)(-10, 0) respectively, as the y-coordinate is zero for all x-intercepts.

Therefore, the points of intersection are (1,0) (1, 0) and 10,0)-10, 0) .

3

Final Answer

(1,0),(10,0) (1,0),(-10,0)

Key Points to Remember

Essential concepts to master this topic
  • Zero Product Property: If ab = 0, then a = 0 or b = 0
  • Technique: Set each factor equal to zero: (x-1) = 0 gives x = 1
  • Check: Substitute x-values back: (1-1)(1+10) = 0×11 = 0 ✓

Common Mistakes

Avoid these frequent errors
  • Sign errors when solving factor equations
    Don't solve (x+10) = 0 as x = 10 instead of x = -10! This gives the wrong x-intercept point. The plus sign means you subtract 10 from both sides. Always move the constant term to isolate x correctly.

Practice Quiz

Test your knowledge with interactive questions

The following function has been graphed below:

\( f(x)=-x^2+5x+6 \)

Calculate points A and B.

BBBAAACCC

FAQ

Everything you need to know about this question

Why do we set y = 0 to find x-intercepts?

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X-intercepts are points where the graph crosses the x-axis. At these points, the y-coordinate is always 0! So we set the function equal to zero to find where it touches the x-axis.

What if the quadratic isn't already factored?

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You'll need to factor it first or use the quadratic formula. Factored form like y=(x1)(x+10) y = (x-1)(x+10) makes finding x-intercepts much easier using the Zero Product Property.

How do I remember which sign to use when solving?

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Think of it as undoing the operation! For (x1)=0 (x-1) = 0 , add 1 to both sides. For (x+10)=0 (x+10) = 0 , subtract 10 from both sides.

Why are the y-coordinates always 0 for x-intercepts?

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By definition, x-intercepts are where the graph crosses the x-axis. Since the x-axis has equation y = 0, all points on it have y-coordinate equal to 0.

Can a quadratic have more than 2 x-intercepts?

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No! A quadratic function can have at most 2 x-intercepts. It might have 2 (like this problem), 1 (touches x-axis), or 0 (doesn't cross x-axis).

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