Domain Analysis: Find Valid Inputs for x² + 2(17/20)

Quadratic Functions with Domain Analysis

Find the positive and negative domains of the function:

y=x2+21720 y=x^2+2\frac{17}{20}

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Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Find the positive and negative domains of the function:

y=x2+21720 y=x^2+2\frac{17}{20}

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Understand the nature of the quadratic function
  • Step 2: Determine when y=x2+5720 y = x^2 + \frac{57}{20} is negative
  • Step 3: Determine when it is positive

Now, let's work through each step:
Step 1: The function y=x2+5720 y = x^2 + \frac{57}{20} is a parabola that opens upwards because x2 x^2 is always non-negative.
Step 2: Since x2 x^2 is always non-negative and 5720\frac{57}{20} is positive, y=x2+5720 y = x^2 + \frac{57}{20} is always positive or zero.
Step 3: The function cannot be negative given that both terms x2 x^2 and 5720\frac{57}{20} are both non-negative and positive, respectively.

However, for determining strictly positive values, it holds true for function value when y>0 y > 0 . This occurs when x0 x \neq 0 , but since y y is indeed non negative for all reals, looking for positive domains here matters less for positive values.

Therefore, the solution to the problem is:

x<0: x < 0 : none

x>0: x > 0 : all x

3

Final Answer

x<0: x < 0 : none

x>0: x > 0 : all x

Key Points to Remember

Essential concepts to master this topic
  • Rule: Quadratic functions x2+c x^2 + c have all real numbers as domain
  • Technique: Since x20 x^2 ≥ 0 and 5720>0 \frac{57}{20} > 0 , function is always positive
  • Check: Test x = 0: 02+5720=5720>0 0^2 + \frac{57}{20} = \frac{57}{20} > 0

Common Mistakes

Avoid these frequent errors
  • Confusing domain with range or positive/negative output values
    Don't think domain means where the function is positive = wrong interpretation! Domain is about valid input values, not output signs. Always remember domain is the set of all possible x-values the function can accept.

Practice Quiz

Test your knowledge with interactive questions

The graph of the function below intersects the X-axis at points A and B.

The vertex of the parabola is marked at point C.

Find all values of \( x \) where \( f\left(x\right) > 0 \).

AAABBBCCCX

FAQ

Everything you need to know about this question

What's the difference between domain and where a function is positive?

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Domain is all possible x-values you can put into the function. Positive values refer to where the output y is greater than zero. For y=x2+5720 y = x^2 + \frac{57}{20} , domain is all real numbers, but y is always positive!

Why is the domain all real numbers for this function?

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Because you can square any real number and add a constant! There are no restrictions like square roots of negatives or division by zero in this function.

How do I know this function is always positive?

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Since x20 x^2 ≥ 0 for all real x, and 5720=2.85>0 \frac{57}{20} = 2.85 > 0 , their sum is always positive. Even at x = 0, you get y=5720>0 y = \frac{57}{20} > 0 !

What does 'none' mean in the answer choices?

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When it says 'none' for negative domains, it means no x-values make the function negative. The function never goes below zero, so there are no negative output values.

Why does the explanation mention x ≠ 0 but then say all x?

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That's a small error in the explanation. Since x2+5720>0 x^2 + \frac{57}{20} > 0 even when x = 0, the function is positive for all real numbers, including zero.

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