Find the positive and negative domains of the function:
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Find the positive and negative domains of the function:
To solve this problem, we must determine when the quadratic function is positive or negative.
The function is a simple parabola opening upwards because the coefficient of is positive (). This indicates the graph of the function is positioned above the x-axis or tangent to it if it has roots (but here it clearly has no zero-crossings due to +2 as constant).
Clearly, since this expression is always non-negative for any real number , plus 2, the value of is always positive.
For , the term is still positive, hence remains positive. Therefore, there is no negative domain for .
For , the quadratic behavior above justifies that is always positive across the entire positive domain of .
By the analysis above:
Thus, the correct choice is Choice 3:
Therefore, the solution to the problem is none, all .
none
all x
The graph of the function below intersects the X-axis at points A and B.
The vertex of the parabola is marked at point C.
Find all values of \( x \) where \( f\left(x\right) > 0 \).
These terms ask where the function outputs (y-values) are positive or negative, not the inputs. For , we need to find where y > 0 and where y < 0.
Since for all real numbers, . Adding 2 gives us . The function never goes below 2!
Look at the coefficient of ! Since , the parabola opens upward. Negative coefficients make parabolas open downward.
Not for this problem! We're analyzing where y is positive or negative. Since , the function is always positive and never equals zero.
This is asking where y < 0 when x < 0. Since the function is always positive (y ≥ 2), there are no x-values that make y negative, hence 'none'.
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