Domain Analysis of y=-1/6x²-5/7: Finding Valid Input Values

Find the positive and negative domains of the function below:

y=16x257 y=-\frac{1}{6}x^2-\frac{5}{7}

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Step-by-step written solution

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1

Understand the problem

Find the positive and negative domains of the function below:

y=16x257 y=-\frac{1}{6}x^2-\frac{5}{7}

2

Step-by-step solution

To solve the problem, we proceed as follows:

  • The quadratic function is given as y=16x257 y = -\frac{1}{6}x^2 - \frac{5}{7} .
  • The coefficient a=16 a = -\frac{1}{6} is negative, indicating the parabola opens downward.
  • The function has no x x -term (b=0 b = 0 ), so the vertex x x -coordinate is 0 0 .
  • Evaluating y y at x=0 x = 0 , we have: y=57 y = -\frac{5}{7} , which is negative.
  • Since the parabola opens downward and y y at the vertex is negative, y y remains negative for all x x values.
  • Thus, there is no positive domain.
  • For x<0 x < 0 , y y is negative for all x x .

In conclusion, the function remains negative for all x<0 x < 0 and is also negative for all else. The answer choice matches:

x<0: x < 0 : all x x

x>0: x > 0 : none

3

Final Answer

x<0: x < 0 : all x x

x>0: x > 0 : none

Practice Quiz

Test your knowledge with interactive questions

The graph of the function below intersects the X-axis at points A and B.

The vertex of the parabola is marked at point C.

Find all values of \( x \) where \( f\left(x\right) > 0 \).

AAABBBCCCX

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