Evaluate 8(x-7)+4(6-2y) with Substitution: x=0, y=-1

Question

What will be the result of this algebraic expression:

$8(x-7)+4(6-2y)$

if we place

$x=0,y=-1$

00:13 Let's set up the problem and find the solution.

00:17 First, substitute the numbers given in the problem and solve step by step.

00:34 Always remember to solve what's inside the parentheses first.

00:43 Next, do multiplication and division before you add and subtract.

00:48 If you multiply two negatives, you always get a positive number.

00:53 And when you multiply a positive by a negative, the result is negative.

01:00 Keep going, following the right order of operations to solve the problem.

01:12 And there you have it, the solution to the question!

We have the given exercise, and it has two variables, X and Y.

In this case, we are given the values of these variables,

Therefore, what we need to do is substitute them in the relevant place in the exercise:

8(x-7)+4(6-2y)=

We know that x=0, so we will replace every X in the exercise with 0:

8(0-7)+4(6-2y)=
8(-7)+4(6-2y)=
-56+4(6-2y)=

We'll do the same thing with y, knowing that it equals -1

-56+4(6-2*(-1))=
-56+4(6-(-2)))=

-56+4(8)=

-56+32=

-24

And that's the solution!

$-24$