Evaluate the Expression: 8(x-7)+4(6-2y) with x=8 and y=5

Question

What will be the result of this algebraic expression:

8(x7)+4(62y) 8(x-7)+4(6-2y)

if we place

x=8,y=5 x=8,y=5

Video Solution

Solution Steps

00:00 Set up and solve
00:03 Substitute appropriate values according to the given data and solve
00:19 Always solve parentheses first
00:29 Always solve multiplication and division before addition and subtraction
00:42 Positive times negative always equals negative
00:48 And this is the solution to the question

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Substitute the given values into the expression.
  • Step 2: Simplify the expression step-by-step.
  • Step 3: Evaluate and find the final result.

Now, let's work through each step:

Step 1: Substitute x=8 x = 8 and y=5 y = 5 into the expression:
8(x7)+4(62y)8(87)+4(62×5) 8(x-7) + 4(6-2y) \rightarrow 8(8-7) + 4(6-2 \times 5) .

Step 2: Simplify the expression:
- First, evaluate 8(87) 8(8-7) . Since (87)=1 (8-7) = 1 , we have:
8×1=8 8 \times 1 = 8 .

- Next, evaluate 4(62×5) 4(6-2 \times 5) . Compute 2×5=10 2 \times 5 = 10 , so 610=4 6 - 10 = -4 .
Therefore, 4×(4)=16 4 \times (-4) = -16 .

Step 3: Combine the terms:
8+(16)=816=8 8 + (-16) = 8 - 16 = -8 .

Therefore, the solution to the problem is 8 -8 .

Answer

8 -8