Evaluate (a·5·6·y)^5: Simplifying a Fifth Power Expression

Exponent Rules with Multiple Factors

(a56y)5= (a\cdot5\cdot6\cdot y)^5=

❤️ Continue Your Math Journey!

We have hundreds of course questions with personalized recommendations + Account 100% premium

Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Simplify
00:02 Let's calculate the possible multiplication
00:05 We'll use the power formula for multiplication
00:08 Every multiplication to the power of the exponent (N)
00:11 Equals each factor separately to the power of the same exponent (N)
00:14 We'll use this formula in our exercise
00:18 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

(a56y)5= (a\cdot5\cdot6\cdot y)^5=

2

Step-by-step solution

We use the formula:

(a×b)x=axbx (a\times b)^x=a^xb^x

Therefore, we obtain:

(a×5×6×y)5=(a×30×y)5 (a\times5\times6\times y)^5=(a\times30\times y)^5

a5305y5 a^530^5y^5

3

Final Answer

a5305y5 a^5\cdot30^5\cdot y^5

Key Points to Remember

Essential concepts to master this topic
  • Power Rule: (ab)n=anbn (ab)^n = a^n \cdot b^n for all factors
  • Technique: First multiply constants: 5×6=30 5 \times 6 = 30 , then apply exponent
  • Check: Each factor gets raised to the power: a5,305,y5 a^5, 30^5, y^5

Common Mistakes

Avoid these frequent errors
  • Only applying the exponent to some factors
    Don't raise just one factor to the 5th power like a30y5 a \cdot 30 \cdot y^5 = wrong answer! The exponent applies to the entire product inside parentheses. Always raise every single factor to the given power.

Practice Quiz

Test your knowledge with interactive questions

Choose the expression that corresponds to the following:

\( \)\( \left(2\times11\right)^5= \)

FAQ

Everything you need to know about this question

Why does the exponent apply to every factor inside the parentheses?

+

The power rule states that when you raise a product to a power, each factor gets raised to that power. Think of (a30y)5 (a \cdot 30 \cdot y)^5 as multiplying (a30y) (a \cdot 30 \cdot y) by itself 5 times!

Should I calculate 30^5 or leave it as is?

+

For this type of problem, it's usually better to leave it as 305 30^5 . Calculating 305=24,300,000 30^5 = 24,300,000 makes the answer unnecessarily complicated and harder to check.

What if I have negative numbers inside the parentheses?

+

The same rule applies! Just remember that odd powers keep the negative sign while even powers make it positive. For example: (2)5=32 (-2)^5 = -32 .

Can I multiply the constants first before applying the exponent?

+

Yes! It's actually helpful to simplify inside the parentheses first. So (a56y)5=(a30y)5 (a \cdot 5 \cdot 6 \cdot y)^5 = (a \cdot 30 \cdot y)^5 , then apply the power rule.

How do I check if my answer is correct?

+

Make sure every factor inside the original parentheses has the exponent 5. Your final answer should have three separate terms: a5 a^5 , 305 30^5 , and y5 y^5 .

🌟 Unlock Your Math Potential

Get unlimited access to all 18 Exponents Rules questions, detailed video solutions, and personalized progress tracking.

📹

Unlimited Video Solutions

Step-by-step explanations for every problem

📊

Progress Analytics

Track your mastery across all topics

🚫

Ad-Free Learning

Focus on math without distractions

No credit card required • Cancel anytime

More Questions

Click on any question to see the complete solution with step-by-step explanations