Value Comparison: Determining the Greater Magnitude

Exponent Rules with Power Comparisons

Which value is greater?

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Determine the greatest value
00:04 According to the laws of exponents, multiplication with the same base(A) with exponents N,M
00:06 will be equal to the same base(A) with exponent (N+M)
00:10 Let's apply it to the question
00:14 We'll use the formula and combine the exponents
00:17 According to the laws of exponents, raising the base(A) with exponent(M) to the power of(N)
00:20 will give us the base(A) with an exponent that is the product of the powers(N,M)
00:23 Let's apply it to the question
00:27 We'll use the formula and multiply the exponents
00:34 According to the laws of exponents, when dividing with the same base(A)
00:37 with different exponents(M,N) where M is in the numerator
00:40 we obtain the same base(A) with exponent(M-N)
00:43 Let's apply it to the question and subtract the exponents
00:47 Always subtract the denominator's exponent from the numerator's exponent
00:52 Let's go through the answers and find the largest one
01:02 This is the solution

Step-by-step written solution

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1

Understand the problem

Which value is greater?

2

Step-by-step solution

To solve this problem, we need to simplify and compare the given expressions.

Let's simplify each:

  • y7×y2 y^7 \times y^2 :
    Using the product of powers rule, y7×y2=y7+2=y9 y^7 \times y^2 = y^{7+2} = y^9 .
  • (y4)3 (y^4)^3 :
    Using the power of a power rule, (y4)3=y4×3=y12 (y^4)^3 = y^{4 \times 3} = y^{12} .
  • y9 y^9 :
    This is already in its simplest form, y9 y^9 .
  • y11y4 \frac{y^{11}}{y^4} :
    Using the power of a quotient rule, y11y4=y114=y7 \frac{y^{11}}{y^4} = y^{11-4} = y^7 .

Now that all the expressions are in the form yn y^n , we can compare the exponents to see which is greatest: y9y^9, y12y^{12}, y9y^9, and y7y^7.

The expression with the highest power is y12 y^{12} , which corresponds to the choice (y4)3 (y^4)^3 .

Thus, the greater value among the choices is (y4)3 (y^4)^3 .

3

Final Answer

(y4)3 (y^4)^3

Key Points to Remember

Essential concepts to master this topic
  • Product Rule: When multiplying same bases, add exponents: ya×yb=ya+b y^a \times y^b = y^{a+b}
  • Power of Power: (y4)3=y4×3=y12 (y^4)^3 = y^{4 \times 3} = y^{12} multiplies exponents together
  • Verification: Convert all expressions to yn y^n form and compare exponents ✓

Common Mistakes

Avoid these frequent errors
  • Confusing multiplication and addition of exponents
    Don't add exponents in (y4)3 (y^4)^3 to get y7 y^7 ! Power of a power means multiply exponents, not add them. This gives completely wrong values. Always multiply exponents when raising a power to another power: (y4)3=y4×3=y12 (y^4)^3 = y^{4 \times 3} = y^{12} .

Practice Quiz

Test your knowledge with interactive questions

Simplify the following equation:

\( \)\( 4^5\times4^5= \)

FAQ

Everything you need to know about this question

Why do I multiply exponents in (y4)3 (y^4)^3 instead of adding them?

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Because you're taking y4 y^4 and multiplying it by itself 3 times: y4×y4×y4 y^4 \times y^4 \times y^4 . Using the product rule, this becomes y4+4+4=y12 y^{4+4+4} = y^{12} .

How do I know which expression has the greatest value?

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First, simplify each expression to the form yn y^n . Then compare the exponents - the largest exponent gives the greatest value (assuming y > 1).

What's the difference between y7×y2 y^7 \times y^2 and (y7)2 (y^7)^2 ?

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In y7×y2 y^7 \times y^2 , you add exponents: y7+2=y9 y^{7+2} = y^9 . In (y7)2 (y^7)^2 , you multiply exponents: y7×2=y14 y^{7 \times 2} = y^{14} . Very different results!

Why does y11y4 \frac{y^{11}}{y^4} become y7 y^7 ?

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When dividing powers with the same base, you subtract the exponents: y11y4=y114=y7 \frac{y^{11}}{y^4} = y^{11-4} = y^7 . This is the quotient rule for exponents.

What if y is negative or a fraction?

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The exponent rules still work the same way! However, comparing values becomes trickier. For this problem, we assume y > 1 so higher exponents mean greater values.

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