Find Increasing Intervals for the Quadratic Function y = (x+2)²

To determine where the function $y = (x+2)^2$ is increasing, follow these steps:

• Step 1: Find the derivative of the function, $y = (x+2)^2$.
  This is $y' = 2(x+2)$.
• Step 2: Identify the critical point by setting the derivative equal to zero: $2(x+2) = 0$.
  The solution to this is $x = -2$, indicating the vertex of the parabola.
• Step 3: Analyze the sign of $y'$ to determine where the function increases.
  If $x > -2$, then $y' = 2(x+2) > 0$, indicating that the function is increasing.
• Thus, the function is increasing for $x > -2$.

Therefore, the interval where the function $y = (x+2)^2$ is increasing is $x > -2$.