Find Increasing Intervals for the Quadratic Function: y = -(x+7)²

Find the intervals where the function is increasing:

y=(x+7)2 y=-(x+7)^2

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1

Understand the problem

Find the intervals where the function is increasing:

y=(x+7)2 y=-(x+7)^2

2

Step-by-step solution

The function given is y=(x+7)2 y = -(x+7)^2 , which is a quadratic function in vertex form. The structural form of this function is y=a(xh)2+k y = a(x-h)^2 + k , where a=1 a = -1 , h=7 h = -7 , and k=0 k = 0 .

The vertex of the parabola is at (7,0) (-7, 0) . Since a=1 a = -1 , the parabola opens downwards. For downward-opening parabolas, the function is increasing to the left of the vertex and decreasing to the right of the vertex.

Therefore, the function is increasing for x<7 x < -7 .

Thus, the solution to the problem is: x<7 x < -7 .

3

Final Answer

x<7 x<-7

Practice Quiz

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Note that the graph of the function shown below does not intersect the x-axis

The parabola's vertex is A

Identify the interval where the function is decreasing:

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