Find the Missing Operator in -5+(5-3·2)+6☐((3+2)·2):2·0

In order to solve the given problem, whether it involves addition or subtraction each of the terms that appear in the equation must be dealt with separately,

This is done within the framework of the order of operations, which states that multiplication precedes addition and subtraction, and that the preceding operations are performed before division and subtraction, and that the preceding operations are for all,

A. We will start with the terms that are on the left in the given problem:

$-5+5-3\cdot2+6$

Simplify the terms that are in the parentheses in accordance with the order of operations, start with the multiplication that is in the terms and continue to perform the operations of addition and subtraction:

$-5+5-3\cdot2+6=\\ -5+5-6+6=\\ 0$$$

We finish simplifying the terms that are on the left in the given problem.

$$B. We will continue and simplify the terms that are on the right in the given problem:

$\big((3+2)\cdot2\big):2\cdot0$

Note that in this term there is a multiplication between the term and the number 0, in addition note that in this term it is defined (since it does not include division by 0), we remember that multiplying any number by 0 will yield the result 0, therefore:

$\big((3+2)\cdot2\big):2\cdot0 =\\ 0$

$$We return now to the original problem, and we will present the results of simplifying the terms that were reported in A and B:

$-5+5-3\cdot2+6\textcolor{red}{☐}\big((3+2)\cdot2\big):2\cdot0 \\ \downarrow\\ 0\text{ }\textcolor{red}{_—}0$

As a result that we find that:

$0 \text{ }\textcolor{red}{=}0$

Therefore the correct answer here is answer A.