Choose the equation that represents the function
moved 3 spaces to the left
and 4 spaces up.
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Choose the equation that represents the function
moved 3 spaces to the left
and 4 spaces up.
To solve this problem, the following steps are necessary:
We begin with the original function:
First, we apply the horizontal shift of 3 units to the left. Moving a graph left involves adding a number to in the equation. Hence, replace with . This manipulatively affects the original function:
Next, we apply the vertical shift of 4 units upward. This involves adding 4 to the function:
Therefore, the equation representing the parabola moved 3 spaces to the left and 4 spaces up is:
Verification against the choices confirms that the correct answer is choice (1):
This is indeed the equation that results after applying the given transformations to the original function .
Find the corresponding algebraic representation of the drawing:
This seems backwards but think about it: when x = -3, the expression (x+3) equals zero! So the vertex occurs at x = -3, which is 3 units left of the original.
Use this trick: Horizontal changes go INSIDE with the x, vertical changes go OUTSIDE. So (x+3) affects horizontal position, +4 affects vertical position.
The transformations work exactly the same way! Whether it's or , moving left 3 and up 4 gives you (x+3)² + 4 or -(x+3)² + 4.
Check the vertex location! The original vertex at (0,0) should move to (-3,4). In , when x = -3, you get y = 4. Perfect match!
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