Finding Y-Axis Intersection Points: y=2x²+10 Quadratic Function

To solve this problem, we need to determine where the given function intersects the y-axis. This occurs when the x-coordinate is 0. Let's find the y-coordinate when $x = 0$.

The function in question is $y = 2x^2 + 10$.
Substitute $x = 0$ into the function:

$y = 2(0)^2 + 10 = 2 \cdot 0 + 10 = 10$.

Since substituting $x = 0$ yields $y = 10$, the point of intersection on the y-axis is $(0, 10)$.

Therefore, the point where the function intersects the y-axis is $(0, 10)$.