Solve y+10=3x²: Finding Y-Axis Intersection Points

Question

At which points does the fuction $y+10=3x^2$ intersect the y axis?

00:00 Find the intersection point of the function with the Y-axis

00:03 At the intersection point with the X-axis, Y equals 0

00:07 Substitute X=0 in our equation and solve to find the intersection point:

00:19 Isolate Y

00:24 This is the value at the intersection point with the Y-axis

00:28 X = 0 as we substituted initially

00:34 And this is the solution to the question

To determine the point where the function $y + 10 = 3x^2$ intersects the y-axis, follow these steps:

Now, let's go through these steps:

Step 1: Set $x = 0$ .

Step 2: Substitute into the equation:
$y + 10 = 3(0)^2$ , which simplifies to:
$y + 10 = 0$ .

Step 3: Solve for $y$ :
$y = -10$ .

Therefore, the point of intersection with the y-axis is $(0, -10)$ .

$(0,-10)$