Solve y+10=3x²: Finding Y-Axis Intersection Points

To determine the point where the function $y + 10 = 3x^2$ intersects the y-axis, follow these steps:

• Step 1: Identify that the y-axis intersection occurs where $x = 0$.
• Step 2: Substitute $x = 0$ into the function equation.
• Step 3: Solve for $y$.

Now, let's go through these steps:

Step 1: Set $x = 0$.

Step 2: Substitute into the equation:
$y + 10 = 3(0)^2$, which simplifies to:
$y + 10 = 0$.

Step 3: Solve for $y$:
$y = -10$.

Therefore, the point of intersection with the y-axis is $(0, -10)$.