Solving x²+y=3: Finding Y-Axis Intersection Points

Question

At which points does the function x2+y=3 x^2+y=3

intersect the y axis?

Video Solution

Solution Steps

00:00 Find the intersection point of the function with the Y-axis
00:03 At the intersection point with the Y-axis, X equals 0
00:07 Let's substitute X=0 in our equation and solve to find the intersection point:
00:16 This is the value at the intersection point with the Y-axis
00:19 X = 0 as we substituted initially
00:24 And this is the solution to the question

Step-by-Step Solution

To solve this problem and determine where the function x2+y=3 x^2 + y = 3 intersects the y-axis, we follow these steps:

  • Step 1: Since the y-axis is where the x-coordinate is zero, set x=0 x = 0 in the given equation.
  • Step 2: Substitute x=0 x = 0 into the equation x2+y=3 x^2 + y = 3 , which simplifies to 0+y=3 0 + y = 3 .
  • Step 3: From the simplified equation, solve for y y . The result is y=3 y = 3 .

This indicates that the point of intersection on the y-axis is (0,3)(0, 3).

Accordingly, the solution to the problem is that the graph intersects the y-axis at the point (0,3)(0, 3).

Answer

(0,3) (0,3)