Locate the Vertex in the Parabola y=(x-3)²

Find the vertex of the parabola

$y=(x-3)^2$

To solve this problem, let's identify the vertex of the given parabola in the form $y = (x - 3)^2$.

The parabola is already given in the vertex form of $y = (x - h)^2 + k$, which is a special case of the quadratic equation where the vertex ($h, k$) can be read directly from the equation.

• Step 1: We compare the given equation $y = (x - 3)^2$ with the standard vertex form $y = (x - h)^2 + k$.
• Step 2: Notice that $h = 3$ and since there is no additional term added or subtracted outside the squared term, $k = 0$.

Therefore, the vertex of the quadratic function $y = (x - 3)^2$ is $(3, 0)$.

The correct choice from the multiple-choice options provided is the one that matches $(3, 0)$.

The solution to the problem is the vertex $(3, 0)$.